drlava
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
When you say you can adjust the current, what range do you get?
When you say you can adjust the current, what range do you get?
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Lava Micro FlexDrive Driver (lavadrive2) fits pens
- Thread starter drlava
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TheMonk
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
Hey Drlava,
Got my two drivers today thanks.
Hey Drlava,
Got my two drivers today thanks.
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
I Pm'd you
I Pm'd you
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
I see you now have the "Flexdrive V3" Models.
How would i go about ordering one?
I see you now have the "Flexdrive V3" Models.
How would i go about ordering one?
Krutz
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
v3 up to 700mA? wow, great news!
paypal sent for two more!
thank you, again!
Manuel
v3 up to 700mA? wow, great news!
paypal sent for two more!
thank you, again!
Manuel
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
Wait...
I didn't get no gold plated driver...
Wait...
I didn't get no gold plated driver...
ColdStl
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
Thanks Dr. Lava, I got mine today.
Is there a particular forward based diode I should use for connecting to 2 cr123's? Catalog/part#?
Thanks Dr. Lava, I got mine today.
Is there a particular forward based diode I should use for connecting to 2 cr123's? Catalog/part#?
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
I believe 2 cr123-a are too much voltage for these it will use one ok or one 18650 !
I believe 2 cr123-a are too much voltage for these it will use one ok or one 18650 !
ColdStl
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
Ok, Thanks!
Ok, Thanks!
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
i think 3v to 5v works perfect for these
i think 3v to 5v works perfect for these
Krutz
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
thats precisely why he wants to connect a diode between the batteries and the driver! the diode drops the voltage by 0.7v, which would be (2x3.0v) - 0.7v = 6.0v - 0.7v = 5.3v which is right in the specs of the driver.
you can use virtually any regular diode for this. "1N400x" is "the" standard-diode, "x" replaced by a number, for example. with such low voltage and current it doesnt matter much. just dont use a regular led, because the voltagedrop wouldnt be 0.7 but 3.3v (for example), and at 300mA to the driver, which is through the led as well, it would die (if its no "big" led). all regular silicon diodes work here. germanium diodes, rare and more expensive, would have a 'drop of 0.3v. nice for some cases, but doesnt help us here. and then there are zener diodes and even some strange gold-diodes(!) with even lower drop. but thats another story
take any diode (you find in any electronical device), shouldnt be more than 0.10$
while at it: buy 10 diodes (and one resistor) and solder yourself a laserdiode-dummy for testing as well!
manuel
john_lawson said:I believe 2 cr123-a are too much voltage for these it will use one ok or one 18650 !
thats precisely why he wants to connect a diode between the batteries and the driver! the diode drops the voltage by 0.7v, which would be (2x3.0v) - 0.7v = 6.0v - 0.7v = 5.3v which is right in the specs of the driver.
you can use virtually any regular diode for this. "1N400x" is "the" standard-diode, "x" replaced by a number, for example. with such low voltage and current it doesnt matter much. just dont use a regular led, because the voltagedrop wouldnt be 0.7 but 3.3v (for example), and at 300mA to the driver, which is through the led as well, it would die (if its no "big" led). all regular silicon diodes work here. germanium diodes, rare and more expensive, would have a 'drop of 0.3v. nice for some cases, but doesnt help us here. and then there are zener diodes and even some strange gold-diodes(!) with even lower drop. but thats another story
take any diode (you find in any electronical device), shouldnt be more than 0.10$
while at it: buy 10 diodes (and one resistor) and solder yourself a laserdiode-dummy for testing as well!
manuel
ColdStl
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
Thanks Krutz!
I saw a pic of the lava flex drive (on another forum) and it had a diode with "9940" printed on it and just wanted to make sure I could use a standard "1N400x" diode in its place.
I appreciate everyones advice on here. Thank you all.
Thanks Krutz!
I saw a pic of the lava flex drive (on another forum) and it had a diode with "9940" printed on it and just wanted to make sure I could use a standard "1N400x" diode in its place.
I appreciate everyones advice on here. Thank you all.
pwnstar
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- Sep 12, 2007
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Re: Lava Micro FlexDrive Driver (lavadrive2) fits
thats precisely why he wants to connect a diode between the batteries and the driver! the diode drops the voltage by 0.7v, which would be (2x3.0v) - 0.7v = 6.0v - 0.7v = 5.3v which is right in the specs of the driver.
you can use virtually any regular diode for this. "1N400x" is "the" standard-diode, "x" replaced by a number, for example. with such low voltage and current it doesnt matter much. just dont use a regular led, because the voltagedrop wouldnt be 0.7 but 3.3v (for example), and at 300mA to the driver, which is through the led as well, it would die (if its no "big" led). all regular silicon diodes work here. germanium diodes, rare and more expensive, would have a 'drop of 0.3v. nice for some cases, but doesnt help us here. and then there are zener diodes and even some strange gold-diodes(!) with even lower drop. but thats another story
take any diode (you find in any electronical device), shouldnt be more than 0.10$
while at it: buy 10 diodes (and one resistor) and solder yourself a laserdiode-dummy for testing as well!
manuel
[/quote]
Im still kind of confused. I put 3 violet LEDs together to give me a 5.2V drop. Is that a good test load for a bluray? or will 120mA kill the 3 violet LEDs?
Krutz said:[quote author=john_lawson link=1209418066/700#713 date=1228207376]I believe 2 cr123-a are too much voltage for these it will use one ok or one 18650 !
thats precisely why he wants to connect a diode between the batteries and the driver! the diode drops the voltage by 0.7v, which would be (2x3.0v) - 0.7v = 6.0v - 0.7v = 5.3v which is right in the specs of the driver.
you can use virtually any regular diode for this. "1N400x" is "the" standard-diode, "x" replaced by a number, for example. with such low voltage and current it doesnt matter much. just dont use a regular led, because the voltagedrop wouldnt be 0.7 but 3.3v (for example), and at 300mA to the driver, which is through the led as well, it would die (if its no "big" led). all regular silicon diodes work here. germanium diodes, rare and more expensive, would have a 'drop of 0.3v. nice for some cases, but doesnt help us here. and then there are zener diodes and even some strange gold-diodes(!) with even lower drop. but thats another story
take any diode (you find in any electronical device), shouldnt be more than 0.10$
while at it: buy 10 diodes (and one resistor) and solder yourself a laserdiode-dummy for testing as well!
manuel
[/quote]
Im still kind of confused. I put 3 violet LEDs together to give me a 5.2V drop. Is that a good test load for a bluray? or will 120mA kill the 3 violet LEDs?
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