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- Dec 9, 2011
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This is exactly rightSo, if I have a handle on this now, what is happening with a FAC lens placed uber close to the diode is the fast axis alone is collimated early (or partially collimated) to reduce the amount of fast axis beam spreading so it more closely matches the slow axis output?
For now, it appears to me what we do with a cylinder pair to square up a rectangle shaped beam to more closely approximate a rounded output is the opposite of what is happening when using a FAC lens close to the diode.
Keep in mind what happens before the collimator lens affects what happens after in a inverse ratiometric way.
For example... Say the raw diode beam angle is reduced so the beam height when it hits the collimator lens is 1/2 what is was before, the FF spot will now be 2X bigger in that axis. This is true of any axis. Make the height where it hits the collimator 2X bigger and the FF of that axis is now 1/2.
This size ratio relationship is easily observed if we go from a 4mmEFL to an 8mmEFL. If no clipping occurs the laser dimensions at the lens will be 2x bigger in height and width with the 8mm lens (this is simple geometry of triangles). And as we know the 8mm will have 1/2 the FF dimensions.
Another thing to think about when trying to "square" MM diodes is the aspect ratio of the emitter. The ratio is usually much greater than the inverted ratio of the raw FA vs SA beam angle.
A rough example from memory: the m140 has roughly a 2um x 15um emitter, about a 1:7.5 ratio. This is what gives the bar shape in the FF. The FF "bar" has nothing to do with the raw divergence of the diode. The m140 raw FA is around 40deg and the SA is around say 10deg. We see that the ratio here is about 4:1. So, even if we manipulate the beam at aperture to be square the FF spot will not be square. To make the FF spot square we could increase the SA by 7.5X.