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FrozenGate by Avery

The Math Thread

LRMNmeyer said:
0.999...=1

I proved this to my friend, and he said "You broke physics!"
Lol7thgrade.

Awesome, 444th post.


0.999... != 1

1 = 1.


There, fixed math.
 





LRMNmeyer said:
0.999...=1

I proved this to my friend, and he said "You broke physics!"
Lol7thgrade.

Awesome, 444th post.

Prove this to us ::)

The verizon client service people need to get a new job where the math isn't done by them....like cleaning toilets. :P I can't believe they can be THAT stupid.....unless it was on purpose....

Oh , btw, I got a 10 in both my math exams, yay :D
 
I lost 42points because i did errors on positive and negative on the algebra part..

Such

3x-b(2b^2-3x)^2
Anyway.
 
Switch said:
[quote author=LRMNmeyer link=1232855187/32#34 date=1233981605]0.999...=1

I proved this to my friend, and he said "You broke physics!"
Lol7thgrade.

Awesome, 444th post.

Prove this to us ::)
[/quote]

n=.999...
10n=9.999...
-n -n
9n=9
9n/9=9/9
n=9/9
n=1
 
LRMNmeyer said:
[quote author=Switch link=1232855187/32#36 date=1234304830][quote author=LRMNmeyer link=1232855187/32#34 date=1233981605]0.999...=1

I proved this to my friend, and he said "You broke physics!"
Lol7thgrade.

Awesome, 444th post.

Prove this to us ::)
[/quote]

n=.999...
10n=9.999...
-n -n
9n=9
9n/9=9/9
n=9/9
n=1

[/quote]


NO.

10n - n = 9n

You stated that:

n = n
0.999... = 0.999...

10n = 10n

9.999... = 9.999...

9.999.../9.999... = 9.999.../9.999...

n/n = n/n

1 = 1

So there you go, that is not valid.
 
Niko said:
[quote author=LRMNmeyer link=1232855187/32#40 date=1234321547][quote author=Switch link=1232855187/32#36 date=1234304830][quote author=LRMNmeyer link=1232855187/32#34 date=1233981605]0.999...=1

I proved this to my friend, and he said "You broke physics!"
Lol7thgrade.

Awesome, 444th post.

Prove this to us ::)
[/quote]

n=.999...
10n=9.999...
-n -n
9n=9
9n/9=9/9
n=9/9
n=1

[/quote]


NO.

10n - n = 9n

You stated that:

n = n
0.999... = 0.999...

10n = 10n

9.999... = 9.999...

9.999.../9.999... = 9.999.../9.999...

n/n = n/n

1 = 1

So there you go, that is not valid.[/quote]
If you don't like that, I summon copy-pasta from http://qntm.org/?pointnine

0.9999... = 0.9 + 0.09 + 0.009 + 0.0009 + ...

= 9·0.1 + 9·0.01 + 9·0.001 + 9·0.0001 + ...

= 9·10-1 + 9·10-2 + 9·10-3 + 9·10-4 + ...

n=[ch8734]
= [ch931] 9·10-n
n=1

n=N
:= lim [ch931] 9·10-n
N[ch8594][ch8734] n=1

= lim ( 9·10-1 + 9·10-2 + ... + 9·10-N )
N[ch8594][ch8734]

= lim ( 9·0.1 + 9·0.01 + ... + 9·0.000...0001 )
N[ch8594][ch8734] \________/
N digits

= lim ( 0.9 + 0.09 + ... + 0.000...0009 )
N[ch8594][ch8734] \________/
N digits

= lim ( 0.999...999 )
N[ch8594][ch8734] \_______/
N nines

= lim ( 1 - 0.000...0001 )
N[ch8594][ch8734] \________/
N digits

= lim ( 1 - 10-N )
N[ch8594][ch8734]

= lim 1 - lim 10-N
N[ch8594][ch8734] N[ch8594][ch8734]

= 1 - 0
= 1
I'm probably wrong. Oh well. /argument
;D
 
lim (10-N)
N[ch8594][ch8734]

there is the problem I can see (fast reading :().

10-[ch8734] = -[ch8734] not 0.




Or this:

lim ( 1 - 10-N ) = lim (-9-N) = -[ch8734]
N[ch8594][ch8734] N-->inf

again, != 0 :P
 
0.9 recurring FOR EVER is equal to 1,. however 0.99999....9 with any FINITE number of nines is not equal to 1.

Anyone that argues is arguing with a University-Challenge-winning professor of mathematics. (not me, my old teacher and all-round legend)

A good way of proving this to people who "see" maths problems visually is to graph successively closer values of .9 against the number of 9's the number contains, you will see a nice curve hopefully, but never reaching 1. If you imagine the curve stretching to infinity number of 9's you will be able to see that it touches 1. The algebraic proof is listed above, as you will be able to see. Basically this problem arises due to people being unable to understand the maths behind infinity.


n=.999...
10n=9.999...
-n -n
9n=9
9n/9=9/9
n=9/9
n=1

this makes sense if you consider that remember that the number.999... means repeat these on to infinity. That is the "leap of faith" you must take when reading the line 10n=9.999...
 
charlie bruce said:
0.9 recurring FOR EVER is equal to 1,. however 0.99999....9 with any FINITE number of nines is not equal to 1.

Anyone that argues is arguing with a University-Challenge-winning professor of mathematics. (not me, my old teacher and all-round legend)

A good way of proving this to people who "see" maths problems visually is to graph successively closer values of .9 against the number of 9's the number contains, you will see a nice curve hopefully, but never reaching 1. If you imagine the curve stretching to infinity number of 9's you will be able to see that it touches 1. The algebraic proof is listed above, as you will be able to see. Basically this problem arises due to people being unable to understand the maths behind infinity.


n=.999...
10n=9.999...
-n -n
9n=9
9n/9=9/9
n=9/9
n=1

this makes sense if you consider that remember that the number.999... means repeat these on to infinity. That is the "leap of faith" you must take when reading the line 10n=9.999...


Math is never about faith, it's about logic. Religion is about faith (and not about logic). And I am not religious in any way ;)

Now, I'm not talking about infinite or finite numbers,

1 = 1

.999... = .999...


But 1 is NOT EQUAL to .999...

I am not being close-minded, it's just not equal!

It doesn't matter if I'm "arguing with a Uni professor", I may not think the same way he does :)



abadcaffeinetrip said:
This is neither a formal nor a rigorous proof but it has helped me explain that the .9999.... concept easily.

Most people agree that .33333...  is equal to 1/3
And that .666666..... =2/3

Therefore .9999...... =3/3

Again, you probably couldn't ever use that as a proof on an exam - but it helps explain it in simple terms :)


Oh my god...


3/3 = 1

There's no way 3/3 = 0.999...
 
Wow...it seems that 0.(9) is equal to 1 ::) However the only "angle" I see it unequal to 1 is visualizing a graph.As you have more digits the number gets closer and closer to 1, asimptotically, so it never reaches 1, just tends to get closer and closer. :-/
 
Niko said:
But 1 is NOT EQUAL to .999...

I am not being close-minded, it's just not equal!

It doesn't matter if I'm "arguing with a Uni professor", I may not think the same way he does :)

Sorry Chuck, they're one and the same number. They are synonymous with one another.

Read the wikipedia page. It explains it a number of different ways.
http://en.wikipedia.org/wiki/0.999...
In mathematics the repeating decimal 0.999… which may also be written as 0.\bar{9} , 0.\dot{9} or 0.(9)\,\! denotes a real number equal to one.
 

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Switch said:
Wow...it seems that 0.(9) is equal to 1 ::) However the only "angle" I see it unequal to 1 is visualizing a graph.As you have more digits the number gets closer and closer to 1, asimptotically, so it never reaches 1, just tends to get closer and closer. :-/

That's exactly how I think about it. I just can't accept that they're THE SAME number.

I know, I know, it is accepted as an equality, but I don't like those kinds of things (though it is sometimes easier to simplify stuff in math by accepting stuff like this). But that's like saying "Bizarre" is "Rare/Weird" when it actually means "Brave".


[edit]Edit: I read the wikipedia article on this, everything is clearer now, this helped:

Code:
Skepticism in education

Students of mathematics often reject the equality of 0.999[ch8230] and 1, for reasons ranging from their disparate appearance to deep misgivings over the limit concept and disagreements over the nature of infinitesimals. There are many common contributing factors to the confusion:
Students are often "mentally committed to the notion that a number can be represented in one and only one way by a decimal." Seeing two manifestly different decimals representing the same number appears to be a paradox, which is amplified by the appearance of the seemingly well-understood number 1.[33]
Some students interpret "0.999[ch8230]" (or similar notation) as a large but finite string of 9s, possibly with a variable, unspecified length. If they accept an infinite string of nines, they may still expect a last 9 "at infinity".[34]
Intuition and ambiguous teaching lead students to think of the limit of a sequence as a kind of infinite process rather than a fixed value, since a sequence need not reach its limit. Where students accept the difference between a sequence of numbers and its limit, they might read "0.999[ch8230]" as meaning the sequence rather than its limit.[35]
Some students regard 0.999[ch8230] as having a fixed value which is less than 1 by an infinitesimal but non-zero amount.
Some students believe that the value of a convergent series is at best an approximation, that .[img]http://upload.wikimedia.org/math/4/6/4/464e677df3cf3b2c393f27350684f709.png[/img]
[/edit]
 


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