New Nichia 9mm 1W 520nm diode (NDG7475T)

[Asmodian]

Well each blue photon contains more energy but the way we measure lasers doesn't count photons but total power.

So for power 1W 445nm = 1W 520nm and the 520nm is putting out more lower energy photons.

 

[AnselmoFanZero]

Doesnt make much sense to me to be honest oO
Still sounds like blue is "more" powerful. The wave, same W, but shorter wave.

 

[Atomicrox]

It's not more powerful.

Think of photons as rocks: the blue laser is throwing a low amount of heavy rocks, while the green is throwing a lot of lighter rocks. But in one second they both throw the same total weight.

The thing is that blue usually burns better (with the same power) because most objects tend to reflect green better.

 

[DashApple]

Optical power is optical power .

1W Blue , 1W red , 1W green , same optical power ,just each photo carries more energy the lower the wavelength you go , thus for the same power there are less of them ,

In terms of photon energy , one photon of 445nm has more energy than one photon of 520nm , one reason low wavelength light is more dangerous as each single photon has more energy and makes more of a mess when it hits things

 

[Asmodian]

The smallest possible unit of blue is more powerful than the smallest possible unit of green (shorter wavelength vs longer wavelength).

With on the order of 10^18 photons per second from a 1W 445nm laser and more from a 1W 520nm laser, the relative power of each photon seems fairly irrelevant.

If we are talking about interactions with chemistry then the 445nm does have more power, each interaction with a molecule can only happen one photon at a time so the shorter wavelength can break higher energy chemical bonds. For pure heating however 1W = 1W.

 

[DJNY]

It´s easy, higher frequence = shorter wavelength = more energy

Talking about wavelengths in particular, they play a role how well a photon is absorbed by a specific surface.
Shorter wavelengths are more likely the get absorbed by substances compared to longer wavelengths.

Hope this helped answering your question a bit Patrick :beer:

 

[Asmodian]

It´s easy, higher frequence = shorter wavelength = more energy

But this isn't true if taking about 1W lasers.

 

[DashApple]

But this isn't true if taking about 1W lasers.

1W is only the optical power ,

if he is referring to photon energy then what he is saying is right , Shorter wavelength = higher frequency = more energy per photon .

 

[Asmodian]

lol I swear no one reads the previous posts.

 

[DashApple]

lol I swear no one reads the previous posts.

Trust me I did .

 

[AnselmoFanZero]

Yes I did read them, and yes that IS what I meant, but I love the way As is thinking
Heavy rock, lower RANGE, but if it hits you, you go down :>

 

[3Pig]

So we are going back to the caveman days? Rock on!

 

[ricktrent4]

I got some of the new 520nm lens in, it was a 2 element lens .I like the 445nm 3 element lens the best and I could not tell a lot in power.

 

[numquamretro]

Any news on beamcorrection for the diode? I´d like to know what divergence can be achieved at a reasonable beam size (lets say 5mm at the aperature).

 

[bloompyle]

I feel the need to point out a valid concern here.

Increasing the power as high as you can with these, will induce a red shift with the diode. That being said, this is bitter-sweet.

It will red shift closer to peak visibility, so it could make it a fraction more visible. Much? No, but it will make a slight difference.

However, it will become increasingly less noticeably "blue". Especially in the 523-525+ range. If you want a teal 1W portable, run these low. Run them at threshold even. It won't be 1W, but you'll have Class IV of likely 515-518.

Just an FYI. More power/visibility, or more uniqueness from the wavelength department? Up to you, but if I ever get one of these, I'll be underdriving it for sure.

 

[ricktrent4]

That is odd ! I could not see a red shift with the diode. do you have a way to test the nm change ?

I feel the need to point out a valid concern here.

Increasing the power as high as you can with these, will induce a red shift with the diode. That being said, this is bitter-sweet.

It will red shift closer to peak visibility, so it could make it a fraction more visible. Much? No, but it will make a slight difference.

However, it will become increasingly less noticeably "blue". Especially in the 523-525+ range. If you want a teal 1W portable, run these low. Run them at threshold even. It won't be 1W, but you'll have Class IV of likely 515-518.

Just an FYI. More power/visibility, or more uniqueness from the wavelength department? Up to you, but if I ever get one of these, I'll be underdriving it for sure.