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Another member PM'd me to point out that these drivers may be poor quality and have current spikes. So not a good idea for a high current build near the limit of the diode.
But for a lower power build, it might be worth it to get some of the effects, like low power and strobe that a lot of the flashlights come with?
Might be worth trying on some cheap reds?
Yes LED's are much more robust than diodes so their drivers don't need to smooth out the spikes as much but there have been some that have been successfully used with the 445's as they are really tough compared to any of the other diodes we had been using previously. The NJG is an example but even that driver when tested showed it had a some good spikes when probed. As far as trying them with cheap red diodes or other lower power diodes would be more at risk as they really can't handle spikes nearly as well as the 445's or even these new high power 635's which is why we use driver that were built with that in mind.
Laser driver - It can be done
Those are awesome, but the Jetbeam is $110.00 so you are starting with an expensive host right off...
I've seen the http://laserpointerforums.com/f67/driver-mod-up-1-8amps-2x-3-7v-3-0v-cells-59336.html thread a whole number of times. I've read it off and on. Something that has always peaked my curiosity though, is why all the amperages seem to have been replaced by the letters "XX".
Was there some sort of legal / liability issue? Was Ave asked to censor the post for some reason?
Yeah, those XXs make me sad.
They don't make me sad - just curious as to the story behind them.
I don't know the story but those are AX2002 ICs, current is calculated by I = 0.25/R so no big deal anyone can use it it's free as in the datasheet?
Weird co-incidence:
- I have a small strip of .33 ohm SMD 0805 resistors staring at me from the DIY boost testing. If I just parallel one on, I should get about 1.7A out.
I know that I've got some of these drivers somewhere. I'll go give it a shot.
if you parallel 2x 0.33ohm resistors you will get 0.165ohm
0.25 / 0.165 = 1.5151515151A so you will get around 1.5A with those
if you parallel 1x 0.33ohm and 1x0.20ohm you will get 0.12453
0.25 / 0.12456 = ~2A
you need 0.147 ohm resistance for 1.7A you need other resistors to parallel :beer:
If the stock is 925mA, that implies a 0.27 ohm stock resistor. If you parallel a 0.3 ohm resistor with 0.27 ohm, you should have 0.142 ohms. That should yield 1.76A.