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260W IR Laser pump handheld?






I'm just going to leave this pic right here, no reason.

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But there is a reason... you are interested in the rifle with the large lens, I bet you have a scary build in mind, I don't know something like, 900W diode array Nichia laser rifle, with that lens that has the beam reaches all the way to Papua 😱
 
Given the physical dimensions of all the components using just the pump modules, a rifle form factor could be more useful.
((((( For safe, responsible and legal use only should go without saying. )))))
However in the interest of laser safety ^ there it is ^ I said it, everyone lase safely.

Actually I would prefer a backpack and wand style build with an active fiber system for longer runtime, higher output and superior beam quality.

These will only get better and more compact in time.

Also interesting would be a C02 slab laser portable system for use as a surgical laser in field, the wavelength choice depending on the use/material to be lased.

Note the size of the optic on this 500W portable with a 240 meter obstacle clearing working range, that's MOPA beam quality.



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I can’t wait for my 500w to arrive, I ordered it 4 weeks ago off Taobao and it just got shipped. I’m designing my own ultra compact >20A buck converter with current regulation. It will be a beast
 
ChatGPT calculated for me what power I will achieve with these amperages. The 1800W boost converter says it can output up to 22A. But it will probably be able to output 23A, because so far all converters output higher voltage and current than described. So if it outputs 23A I will put it in. But if it is 22A I will lose 45W of power, and that is not a small amount
 

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It's a used array and likely not going to hit peak anyway, plus driving at less than max is a good idea to keep it alive and it gives you a safety margin in case of a spike.

Also you won't notice any difference between 900 or 1000 watts, not blasting a brick or block of wood.
Now if you were manufacturing all day then your 900W machine would turn out less product than your 1000W machine over time, but that's why these pulled pumps are being sold off, they already have lost some efficiency and been replaced.

That said @ 22A you should get plenty of burning power..... I might even start @ 20A just because a used diode array may have a lower foldback, that is you might get more light and less waste heat @ 80-90% of rated max.
 
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For this 500W, the battery is important. Given that I will use an inverter, I will need a suitable BMS. It is good to have at least 20-30% reserve. In this case, 25.2V with a 40A BMS will not be able to handle 45V and 22A operation. If the BMS is 25.2V 60A is ok. But I have a 6S 40A BMS. Therefore, I will make two 5S1P batteries connected in series with a 100A BMS. This way I will have a large reserve, because the voltage will be 42V with fully charged batteries and the inverter will not be loaded. It is also limited to 40A input and cannot handle a 12,16 and 24v battery. 990W is needed for these 45V 22A, considering the losses from the inverter, 1100W will be needed at 90% efficiency of the inverter, if we put a fan and other things it becomes even more. The 25.2V battery with a 40A BMS is weak with its 1008W, and if the voltage drops a little to 24-23V, for example, it will stop working completely. Therefore, two batteries connected in series 5S1P at 42V with a 100A BMS will give 4200W of power. Enough for my purposes. The converter will work with ease. It will only need 28-30A of input current depending on the voltage drop
 

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Forgive my ignorance, but I saw that in this new 500W IR of yours, there are 24 small green modules with their respective mirrors, which in the end form a single beam, always ignorant, I calculated 24 small green modules multiplied by 50mW, the mathematical result is 1,200, how do we get to 500W?
 
Forgive my ignorance, but I saw that in this new 500W IR of yours, there are 24 small green modules with their respective mirrors, which in the end form a single beam, always ignorant, I calculated 24 small green modules multiplied by 50mW, the mathematical result is 1,200, how do we get to 500W?
24 emitters in total. Each one at full power will produce about 20W of power. 500 divided by 24 = 20.8W of power
 
24 emitters in total. Each one at full power will produce about 20W of power. 500 divided by 24 = 20.8W of power
Now i understand.. thanks! do you want to teach me how to build laser pointers? from the basics to your levels, over time of course.. i have something ready, but i didn't make them myself.. except for the very simple ones where you just solder two cables and go.. have you seen the Thread My Laser Collection? if you want take a look..
 
Now i understand.. thanks! do you want to teach me how to build laser pointers? from the basics to your levels, over time of course.. i have something ready, but i didn't make them myself.. except for the very simple ones where you just solder two cables and go.. have you seen the Thread My Laser Collection? if you want take a look..
There is enough information in the forum. Actually, there is nothing for me to teach you. Ready-made parts for lasers are sold. In all my lasers that I have made, I have used a lathe to make the radiators where the diode goes. This is not so simple.
 
If you have a yvo4/ktp crystal set that's 15% efficient then in theory 60W of 532nm
If you have a yvo4/ktp crystal set that's 25% efficient then in theory 100W of 532nm

However you will have to manage all that waste heat.

You could pulse your pump laser array and you could also employ a Q-switch however you don't have just a single beam from your pump, rather a bundle of knife edged beams, so mode hopping could be an issue.

That said I have had limited experience making dpss lasers work, I can tell you the alignment can be picky.
 
There is enough information in the forum. Actually, there is nothing for me to teach you. Ready-made parts for lasers are sold. In all my lasers that I have made, I have used a lathe to make the radiators where the diode goes. This is not so simple.
Ok thanks anyway ..
 


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