Well, I'll reveal the process how to figure current for it.
In the op amp I'm using there is a 1k ohm resistor. Literally INSIDE of it, so it removes the need for an external one.
Now, anyway, to figure gain, there is another resistor that is placed on the op amp's output, in series with the potentiometer.
Thr resistor should be 12k ohms. Meaning when the pot is set to zero, or around it, the gain should be 12.
The voltage reference of the IC is 500 mV. To figure sense voltage divide 500 by 12.
500 / 12 is 41.666 mV of sense voltage.
Now I = E/R, correct?
So, 0.041.66 / 0.015 ohms (that's the sense resistor's value!) and you get a max output of 2.77 amps, which allows for some leeway in terms of the pots ACTUAL value.
If the resistor was 6k, then it would just be a higher current limit set by the pot. Somewhere around 3-4 amps (the driver can't do 3-4 amps though! Max is 2.3-2.4 amps!)
I'm talking to Yob about it to see what's up.