Here is a comparison of the raw with a real Osram diode the PLT 450B. This looks near violate next to it. You can also see the mode lines in the diodes received so it is definitely multimode.
I concur, I'd see if PayPal could refund you and you get to keep the diodes. Amazon does this and I think you could talk PayPal into doing this but if not, my offer still stands and will get one for my collection
Can you post a picture compared to a 405nm I want to see how big of a different it is. Also that really sucks it is a scam hope you can get your money back.
- Well time to add that website to the " Blacklist" Sta.
- It sound too good to be true since the very beginning... Both O$R@m and N said that they only sell to end system builder and not consumer nor reseller on their website if nobody noticed. How could this company in question sell for 10 times less than other well established corporation? ... at best these were offered at $800-$1000 when bought in bulk quantity of 50-99. No company would even be in their right mind to buy 100,000 pieces even if it is at the price of $100 for a fairly new technology that is still in prototype phase!! (100,000 x $100 = ..?..).
- Dtr's effort will be greatly appreciated by the forum.
We should all bombard those idiots with dishonest emails so they know how many peaple were expecting what they were advertising, this is heartbreaking, I might still buy one!
Woke up this morning to see this news, now I want to go back to dreamland again
Firstly, it is not what was advertised so get a refund.
Secondly, if you do get to keep them, then definitely get them spectro'd. By the looks of it they are 430-435nm.
In order to really satisfy the wavelength collectors on this forum, we need something that will fill the 40nm gap between the 405 and 445. So 425nm is ideal.
But, we are still no closer to cheaper and more accessible 488's :scowl:
Darn! Sucks to hear these indeed aren't 488nm diodes but something else, although if they are in the ~420nm/~430nm range as other members have mentioned it may still be not a complete loss