voltage

[jamilm9]

Am i right in saying that the higher the nm.The more voltage needed.808nm needs 2 volts 650 needs 3,violet needs 4.5

 

[GooeyGus]

In diodes that seems to be the trend thus far, But I wouldn't assume it to be a rule at all.

 

[jamilm9]

isn't sharp releasing a 366nm laser diode.That would probably need 5 volts. :

 

[styropyro]

For most of the diodes today that is true. Some of those LDs around 1500nm only need around a volt IIRC.

 

[Switch]

Am i right in saying that the higher the nm.The more voltage needed.808nm needs 2 volts 650 needs 3,violet needs 4.5

No , that is completely off. : : Look at your example: 808 is the highest nm and needs the lowest voltage.

: : :

 

[jamilm9]

really but doesn't 1064nm double into 532nm.

 

[Switch]

really but doesn't 1064nm double into 532nm.

The frequency doubles, the wavelength halves (1064=2 x 532, obviously). Frequency is measured in Hz , wavelength is measured in nm , so when you said nm , I assumed wavelength. :-/

 

[jamilm9]

ok(i have 405 posts that violet)

 

[rkcstr]

Not sure if its just a coincidence or not, but higher frequency light (shorter wavelength) has higher energy, so maybe that's why they require more voltage for emission compared to lower frequencies (longer wavelengths).

 

[jamilm9]

maybe

 

[Switch]

Yeah , but the power is the same, it's just that with shorter wave diodes, more of the input power is transfered to heat :

 

[GooeyGus]

Yeah , but the power is the same, it's just that with shorter wave diodes, more of the input power is transfered to heat :

Exactly... I say its that the shorter wavelength diodes are just less efficient than the IR diodes, most likely just being due to newer technology. IR seems to be the most efficient. Who knows, just a theory.