V5 Flexdrive cutoff voltage

[mfo]

The cut off voltage for a v5 flexdrive is 2 volts, right? If I add a diode in series with the driver, then technically the cut off voltage will be 2.7 volts, right?

Reason I ask is because I'm using a CR2 host, and CR2's are not protected. If I make the cut off voltage 2.7 volts instead of 2 volts, then I shouldn't have to worry about over discharge, correct? Thanks.

 

[daguin]

The diode doesn't change the driver, just what is coming into the driver.

Peace,
dave

 

[mfo]

I should have been more clear

If a battery sags down to 2.7 volts, and I have a diode between the battery and that driver, then the driver will cut off right?

 

[Hemlock_Mike]

mfo ---
You may need to direct this question directly to DrLava but IIRC, the V5 has a reverse polarity protection built in which may give you that extra 0.7 volt edge. If the circuit uses Shottke diodes, then some battery protection may be provided.

HMike

 

[mfo]

Thanks Mike, I will shoot him a PM.

 

[drlava]

Hi mfo, the reverse polarity protection on the FlexDrive is highly efficient - it presents almost no additional voltage drop to the driver. If you are using an unprotected cell, yes your series diode solution should perform as expected.

 

[mfo]

Hi mfo, the reverse polarity protection on the FlexDrive is highly efficient - it presents almost no additional voltage drop to the driver. If you are using an unprotected cell, yes your series diode solution should perform as expected.

Thanks Dr. Lava! +1