Super quick question!!

[GooeyGus]

I'm building a circuit to run my argon in current mode. It calls for one 5kohm resistor which is used for voltage drop. Do resistors work the same when used for voltage as current? For example, it calls for one 5k. If I use two 10k in parallel will I get the same result voltage wise?

 

[GooeyGus]

If anyone was wondering, the answer is "yes". I hooked everything up and got the result I was expecting using two 10kohm resistors in parallel for voltage drop, instead of one 5kohm.

 

[Rhith]

Ohm's Law. Learn it. ;D



(In a joking tone of course!)

 

[SenKat_Stonetek]

Answered yourself before I could jump in, dangit

 

[Maelstrom]

If anyone was wondering, the answer is "yes". I hooked everything up and got the result I was expecting using two 10kohm resistors in parallel for voltage drop, instead of one 5kohm.

(1/10)+(1/10)=(1/R)
R=5

 

[Hemlock_Mike]

SUPER --  Ohm's Law LIVES  ;D   Learn it, Love it, Trust it.  For DC circuits,  It's the LAW  ;D

They work with voltage AND current at the same time according to the equation.

Mike

 

[GooeyGus]

I know ohms law well ;D I was super tired and my brain wasn't working right. lol... I just always use resistors for current drop, and I know how they work in parallel with current, I just wasn't sure if it worked the same way when dropping voltage. Another thing that was throwing me was that I didn't know the current, and I was too lazy to work everything out in my head... so I figured I would just post ;D ;D

 

[Kenom]

ahhh it's the lazy poster that strikes again!!! doggon that guy. I think we've all had our fair share of brain farts and laziness combined to make some very pathetic posts on this forum. LOL

 

[GooeyGus]

It was like 3am and I just wanted to see 200mW of argon laser ;D