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Thanks for all the info right here! I'm planning on using one of these diodes with one 4.2v 6000mAh Li-ion battery and a fixed current driver set at 220mA. Heat sinked diode of coarse. My question is; is that to much voltage? Should I just stick with one 3.7v?
Thanks for taking the time to help.
That particular diode/PL520 runs nicely at 8.0~8.1 all the way down to 7.0 VDC without a current regulator, believe it or not, but at 8.2~8.4 VDC it will dim and not come back until the voltage drops down to somewhere between 8.1 to 8.2 VDC. However, it must have a good heat sink if you are running it without a current regulator as it will put out about 100mw which is twice its rated output power. For best single mode TEM00 output, best to run it closer to its rated output power.
If you are going to use it with a constant current regulator, you need a boost driver for it to increase the voltage from a single 4.2 VDC battery to the voltage it needs. Here's a spec for the diode:
http://www.dpss.ro/datasheets/PL_520_2012-10-23.pdf
This is the only laser diode I know of which will run without a CC regulator, my diodes have not died from such abuse, but I cannot guarantee every PL520 will act the same. The specs say 7 to 8 VDC is the operating voltage at 200 ma for 50mw output, you can increase the current to get more power out but I am not sure how high you can increase it without shortening its expected operating life.
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