jayrob
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- Sep 21, 2007
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Re: Open Can with TEC
I read this over carefully and I think I am starting to understand. Please give me some more direction here... I am trying to drive:
* 2 DDL circuits - 2 volts regulator drop out each? Plus 1.25 volts each - 6.5 volts??
* 1 open can LD - 3 volts? Gazoo, you are using this LD...can I figure 3 volts?
* 1 peltier - ?? Gazoo?? Same 12 volt peltier you gave me a link to from e-bay but I know it doesn't need 12 volts. Maybe 2 volts?
* 1 fan using a 5 volt regulator chip - 5 volts
All from 1 battery source. Maybe an 11.1 volt lipo pack? Or if you think I will need more voltage, the next step up for lipo is 14.8 volt.
Also, these lipo packs are made usually for a high current demand. Will a lipo fry everything, or will the circuits just take what they need?
Thanks for your guy's help,
Jay
If I supply 6.28V to the circuit when driving a 16X DVD burner diode at 250mA (the sense resistor is set to 5 Ohms), about 2V is lost because of the regulator dropout, there is a 1.25V drop across the sense resistor, and let’s say the voltage drop of the LD at 250mA is 2.8V. So that’s 2+1.25+2.8=6.05V this time there’s only .23V for the LM317 to get rid of. But wait, when I applied the load to the battery the voltage began to drop. It seems that under load they can only provide 1.48V per cell. That’s only 5.92V, which means that the LM317, no matter how high it tried to raise the voltage, can only get the sense voltage up to 1.2V and at 1.2V the 5 Ohm sense resistor will pass only 240mA. Our regulator is now dropping out, and this was with fresh cells!
I’m sure you can easily see now why when driving a red LD with a forward voltage drop of nearly 3V you must supply more than 6V to the circuit, and were you driving a Blurry LD which has a forward voltage drop of almost 5V, you must supply the circuit with at least 8V.
Now what would happen if I tried to attach a load to the circuit where the sense resistor had a range of 2 Ohms to 100 Ohms, was set to 2 Ohms, the circuit was supplied with 6V and the load was trying to take 5V? Well, that load sure wouldn’t see 5V, but it might see 3.5V, and with the LM317 doing all it could, it could probably only get the sense voltage up to about 0.31V. 0.31V divided by the 2 Ohm sense resistor (there’s Ohm’s Law again) would only give about 155mA. (Does that sound familiar?)
I read this over carefully and I think I am starting to understand. Please give me some more direction here... I am trying to drive:
* 2 DDL circuits - 2 volts regulator drop out each? Plus 1.25 volts each - 6.5 volts??
* 1 open can LD - 3 volts? Gazoo, you are using this LD...can I figure 3 volts?
* 1 peltier - ?? Gazoo?? Same 12 volt peltier you gave me a link to from e-bay but I know it doesn't need 12 volts. Maybe 2 volts?
* 1 fan using a 5 volt regulator chip - 5 volts
All from 1 battery source. Maybe an 11.1 volt lipo pack? Or if you think I will need more voltage, the next step up for lipo is 14.8 volt.
Also, these lipo packs are made usually for a high current demand. Will a lipo fry everything, or will the circuits just take what they need?
Thanks for your guy's help,
Jay