tuskiomi
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- Jan 28, 2015
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Alright, enthusiasts.
i am going to do some of the math in what it would take to make a viable laser rifle.
So, i'm going to define some arbitrary numbers here, that we will use to math our way through.
1)the lethal dose of laser is enough energy to vaporize 10 mols of water (about 200 grams)
2)the absorbance of the target is .3 (70% of the energy is not absorbed)
3)laser effeciency is about 25%
4)we want to have to shoot the enemy for more than 1/4 of a second.
Alright, first off. We look to mine out more constants.
i) according to wikipedia the energy of vaporization of water at body tempreture is 43500 Joules per mol (43.5 KJ/mol)
Actually, i think that's the only constant that we need.
calculations
so, you want to vaporize 10 mols of water in .25 seconds?
10 mols of water is 435KJ of energy that we hope to get in .25 on the clock, eh?
that's about 1.740 Mega watts.
that's a class V laser putting out 1,740,000 watts of photon energy.
that's if you're bare nekkid, and you just take in the energy.
according to above, we are only absorbing 30% of the energy at best.
this bumps us up to 5.8Mw. (That's a capital M for MEGA).
at 25% effeciency that bumps us to 23.2MW of power dissipation
at 3.7 volts that's 6270 Amperes.
if you're looking to do that, aside from the diode, it's possible. Just hook up 41 car batteries in parallel
And the diode may be possible, too. livermore is creating a supposed 1Pw laser (1,000,000,000,000,000 watts). If the laser could fire for a quarter of a second, it would be enough to kill 4,347,000 humans in one go.
Go figure.
i am going to do some of the math in what it would take to make a viable laser rifle.
So, i'm going to define some arbitrary numbers here, that we will use to math our way through.
1)the lethal dose of laser is enough energy to vaporize 10 mols of water (about 200 grams)
2)the absorbance of the target is .3 (70% of the energy is not absorbed)
3)laser effeciency is about 25%
4)we want to have to shoot the enemy for more than 1/4 of a second.
Alright, first off. We look to mine out more constants.
i) according to wikipedia the energy of vaporization of water at body tempreture is 43500 Joules per mol (43.5 KJ/mol)
Actually, i think that's the only constant that we need.
calculations
so, you want to vaporize 10 mols of water in .25 seconds?
10 mols of water is 435KJ of energy that we hope to get in .25 on the clock, eh?
that's about 1.740 Mega watts.
that's a class V laser putting out 1,740,000 watts of photon energy.
that's if you're bare nekkid, and you just take in the energy.
according to above, we are only absorbing 30% of the energy at best.
this bumps us up to 5.8Mw. (That's a capital M for MEGA).
at 25% effeciency that bumps us to 23.2MW of power dissipation
at 3.7 volts that's 6270 Amperes.
if you're looking to do that, aside from the diode, it's possible. Just hook up 41 car batteries in parallel
And the diode may be possible, too. livermore is creating a supposed 1Pw laser (1,000,000,000,000,000 watts). If the laser could fire for a quarter of a second, it would be enough to kill 4,347,000 humans in one go.
Go figure.
