Why do diode laser wavelengths usually end in 5? Does that have to do with the semiconductor material?It can be done... But there's almost no reason not to use a diode for that wavelength unless you're doing some real finicky science. Since that's usually associated with the blue component in display technology diodes are probably the answer to every problem anymore.
Also look at 488nm. You can get this wavelength with just about every laser process. Argon gas, dpss, opsl, fiber, diode, etc. Each has their own set of advantages and disadvantages depending on the application.
A good rule of thumb, if the wavelength ends in 0 or 5, it's likely a diode. Ex 405, 445, 450, 465, 505, 520, 635, 650. Then you have odd cases like 488 which will often be listed as 490.
Ah interesting. Is there any reason why the advertised wavelengths for DPSS lasers are more accurate? This is interesting. I never noticed how diode lasers are always in increments of 5 because of the batch error.No - the reason is diode wavelengths aren't going to be as precise in most situations. Manufacturing differences can make two diodes in the same batch noticeably different wavelengths, so usually an average wavelength is what is advertised. Then in the specs they state something like +/-5nm to account for the differences you may get.
Typically they round off the number to make it more human readable, going by 5s is just usually what ends up happening in a product listing. No reason other than having a pretty number.
Yes, It has to do with the Neodymium expulsion wavelength as being ~1064nm. Double the frequency of that to 532nm and there you are. The most frequently used doubling crystal is potassium titanyl phosphate, or KTP.Ah interesting. Is there any reason why the advertised wavelengths for DPSS lasers are more accurate? This is interesting. I never noticed how diode lasers are always in increments of 5 because of the batch error.