- Joined
- Jun 4, 2011
- Messages
- 137
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I have often wondered this: Why don't we measure the "optical efficiency" for lenses, i.e. a "lens power derate" which would be measured by (optical output with lens/ optical output no lens)?
It would make power comparisons between lenses very simple. Right now, all threads I see are on "AAA lens is X% more power than BBB lens, and BBB lens is Y% less power than CCC lens." It is very confusing. Especially because there is no baseline information on actually how efficient any single lens is. We are making relative, not absolute, comparisons. (Please direct me to this if I am wrong, there is a lot of information on this forum.)
I could see it possibly being a challenge to measure raw diode output, due to the divergence of the diode as well as heat radiation. (Well put by RHD in this post: http://laserpointerforums.com/f54/calculating-efficiency-questions-65642.html#post942835)
However, I think the heat could be treated as a "systematic error" and eliminated if the experiment is conducted properly.
Any thoughts??
Regards,
-J
It would make power comparisons between lenses very simple. Right now, all threads I see are on "AAA lens is X% more power than BBB lens, and BBB lens is Y% less power than CCC lens." It is very confusing. Especially because there is no baseline information on actually how efficient any single lens is. We are making relative, not absolute, comparisons. (Please direct me to this if I am wrong, there is a lot of information on this forum.)
I could see it possibly being a challenge to measure raw diode output, due to the divergence of the diode as well as heat radiation. (Well put by RHD in this post: http://laserpointerforums.com/f54/calculating-efficiency-questions-65642.html#post942835)
However, I think the heat could be treated as a "systematic error" and eliminated if the experiment is conducted properly.
Any thoughts??
Regards,
-J
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