IgorT
0
- Joined
- Oct 24, 2007
- Messages
- 4,177
- Points
- 0
jayrob said:About your driver set up... This is interesting. What's the math there? 12.6/68(ohm) is 185mA's...right?
Then, as the voltage drops to say 3.6 X 3 = 10.8 volts/68(ohm) will be about 158mA's...
Jay
You have to subtract the Vf of the diode from the battery total voltage, to get the current.. So it's closer to 105mA, if the Vf of the diode is assumed to be 5.4V. But the Vf changes with the current (and heat), and the current changes with the battery voltage, so there are too many factors involved, to calculate the current preciselly this way.
Now this approach can work, if you make sure the max current with full batteries is ALWAYS under the max safe current, but is't not a good approach. The power is different every time you turn the laser on, and drops with the battery voltage. And if you put different batteries in, you can still kill the diode. The internal resistance of the batteries alone influences the current in this setup.
Event Horizon: The money you "saved" on the driver (i read your other thread) killed two of your diodes.. With three Li-Ions, Rkcstr's micro driver for $5 - $10 (depending on the version) would work PERFECTLY. Your power would be the same every time you turn the laser on, right down till the batteries would be completelly empty, and your diode would be fully protected, cos the current can not go higher, regardless of the input voltage (up to 35V or so), when you use a linear driver..
And that driver also fits into an AixiZ module, so you can use it wherever you have room for an AixiZ module, as long as you also have room for three Li-Ions for blu rays or two Li-Ions for reds..
Now since this one is already working and isn't in any real danger, you may not want to take it appart to put in a real driver, but next time, spend the few dollars and save a diode or two.
Not only will your power always be the same regardless of the batteries, you can also push the diode harder with a driver, and still be safer!