I am talking about comparative beam visibility in conditions where particles exist to scatter light, I know there is no beam from even the strongest of lasers in a matter free environment as with no matter to scatter light, a visible beam can not exist. I also mean the comparison of two lasers in exactly the same atmospheric conditions at the same time, not at different times. If the conditions are the same, the brightness can be compared. I know there are many facts that could create differing results, but i'm not looking for an exact answer, what I want to know is generally speaking what handheld diod elaser will have a beam brighter than all others when particles in the atmosphere exist to scatter light. So not lasers being seen in different conditions, imagine comparing all handheld lasers at the same time outside during the same night where the conditions the lasers are in are identical. With identical scattering conditions, the brighter beam would be obvious. This is what i am looking for. Of course, the ultimate solution would be for me to test out many lasers and see for myself, but unlike the vets I dont have the resources to perform such experiments. Someday
You come a full circle to a dead end. The best answers anyone can give, you already have.
A 1W 520nm or 532nm will be brighter than a 7W 445nm (if you are talking about the broken laser in previous posts it was actually a 6.3W ~ 445nm, if I remember correctly) plug in the numbers --the relative brightness tool compares brightness of different wavelenghts under very well defined and established identical conditions. : Relative Laser Beam Brightness Calculator: (445nm 6300mw) vs. (532nm 1000mw)
The extent to which the conditions you use are dfferent will produce a different result but it is generally a good guide is all anyone can tell you.
What your own subjective impression/perception will be is what you are trying to forecast/imagine. The relative brightness tool is a pretty good approximation/indicator. Nobody can tell you exactly what it will be exactly--will be it is unique to your eyes and the enviormental circumstances you view the lasers in. You are not going to be measuring the brightness differences anyway so...
Exact visibility and brightness of the same or different wavelenghts at same or different output powers that you encounter depends upon the exact conditions/many things, among them: ambient light, atmosphere and size and shape of particles in it, output power density, divergence, wavelength you are considering, and your eyes response curve and so on.
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