I would do the switching on the base side of the driver transisitosrs using this circuit and 1n4148 diodes. Your design here adds another 0.7 volt drop to your LD's.
I assume you're using NPN transistors for drivers and it's more efficient to switch the low current parts.
Hi Mike, yes they are NPN transistors, I am adapting an existing circuit so I will need to look to see if I can put this the other side of them....The main thing is though that this looks a possibility.
What exactly are you connecting on the right hand side of that schematic?
If both devices are the same voltage (e.g. 5V powered laser modules), it would work fine. On the other hand, if one is a red laser diode, and the other is an IR pump diode, it would not work very well, because the IR diode has a lower drop voltage and would consume all the power coming from the middle input.