IgorT
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suiraM: Very interesting. I was going to suggest that IgorT test his hypothesis by ramping up the current on an LOC to 640mA, then rapidly switch it off and back again. If the diode survives, thermal stress would indeed seem to be the culprit, and if it dies, then back to the drawing board. But now I wonder if the cooling rate upon switching off is great enough that in order to perform the experiment in a meaningful way, the switching would have to be done by a microcontroller instead of a slow human hand? Hmmm... just random thoughts...
This is exactly what i've been thinking!
See, the way i did it, was, i ramped up the current to 640mA, wondered how the hell the diode is not dead yet, took it out of the testing apparatus and mounted the diode in a new (cold) heatsink, and started assembling the laser...
By the time the laser was done, the diode was very cold. And when i turned the laser ON, the diode died so rapidly, that i never even saw the optical pulse that killed it, just the result..
Only after repeating this two or three times, did it occur to me, that maybe i should try ramping up the current to 640mA several times during testing. I was hoping this would eliminate diodes that can't survive those currents, without having to waste the time to build a laser, just to see the diode die every time...
I was thinking, that perhaps, the diode can only get to those currents and powers once, and gets damaged enough during the first test, that the next time it dies. So with the next one, i ramped it up twice. It survived! In a laser, again dead at first powerup...
What i did not test, because it only occured to me afterwards was just what you said above..
Thing is, on my diode analyzer i don't always have to start from zero.. I could simply turn the diode OFF at 640mA let it cool off and turn it back ON again. This way i would find that one diode, that could survive a rapid powerup, without wasting the time to build a laser around it first (this was when i still thought such a diode must exist - because of Billg's 510mW LOC)...
I could also test what would happen if i turned it OFF WITHOUT allowing it to cool off before turning it back on again!
This would definitelly be an interesting thing to test, and i will, as soon as i have time to "waste".
When testing this, i should perhaps even reduce the heatsinking, to make sure it doesn't cool off too much during the time it's OFF..
Or, as you said, turn it off for a very short time, using a computer interface or an MCU.
However, even if i do try this and the diode survives a rapid powerup when hot, this still leaves AT LEAST two possibilities:
1. Thermal stresses were avoided, since the diode was still hot from before
2. Optical flux did not go far above the previously measured point, since the diode was powered up hot, with the efficiency still reduced from before.
But in all likellyhood, it's the combination of both (or more?) factors..
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Then again, the whole reason i was pushing diodes to these absurd currents was Billg's freak 500mW+ LOC...
I was trying to find one diode that could survive the sudden powerup to these currents and powers...
But after thinking about what he told me - he accidentally selected a fixed 3.3V voltage regulator, instead an adjustable one, that could be configured for constant current - it suddenly occured to me that i can't really replicate his results with a constant current driven laser and a rapid powerup!
I was trying to replicate his results under completelly different circumstances!
What i did not realize until he told me he used a constant voltage source was, that when he turns his laser ON with a cold diode, the diode's Vf is higher than it will be, once it's hot! And in his laser, this means that the current starts lower than at the 780-820mA he measured!
The diode then starts warming up from the current, it's Vf drops, and more current starts flowing through it since the voltage is constant...
The power increases and due to more current the diode also produces more heat, warms up to a higher temperature and it's Vf drops further, allowing the current to climb further - over and over again...
This is a good scenario for a thermal runaway, but he seems to have given it just enough heatsinking, so that the current then stops climbing at around 800mA..
Basically, his constant voltage source behaves almost like a slow powerup!
- A constant current source will push the diode to the full current immediatelly, and then keep it there.
- A constant voltage source will allow the current to change with temperature - the hotter the diode, the more current will flow!
This is why we don't use constant voltage to power diodes... It's actually dangerous. But in the opposite way than with constant current.
At a constant current, a cold diode will produce more power - if a diode was supercooled, it could die at a current it can normally survive!
But under normal circumstances, constant current is the safest way to power diodes - as a diode warms up, it's Vf drops, and the driver will reduce the output voltage, to keep the current constant. Additionally the efficiency drops, and the diode drops in power, meaning the optical flux is lower, and the stresses actually reduced, when the diode warms up in a constant current setup!
At a constant voltage, a cold diode will produce less power, as it will allow less current to flow through, due to a higher Vf! But it will start warming up, the Vf will drop and the current will increase. The more it warms up, the higher the current will become!
In Billg's case, it is heat that gradually raises the current from something the diode can evidently survive even with a sudden powerup, to the current where it produces those absurd amounts of power!
Since i did not know just how his accident happened and what the driver was like before i started killing diodes, i was trying to replicate his experiment, but under completelly wrong circumstances...
Billg, by accidentally selecting a fixed constant voltage source, already introduced some sort of a "gentle" powerup into his laser. Altho the first part of the powerup is still rapid in his case, but evidently low enough for the diode to survive, and only after that does the diode climb to it's final current and power.
This means, that a constant current driver with a gentle power-up would be even better, as it would get to the final current even more gently, than the constant voltage source - the entire slope would be gradual - and it would also keep the current constant afterwards, eliminating the possibility of a thermal runaway....
I believe the constant voltage source explains HOW and WHY he was able to make a 500mW+ laser, and it shows, that using a constant current source with a slow power-up will be even "nicer" to the diode, increasing the chances of succesful replication of his results. :yh:
P.S. It does not mean that CV is good for diodes however! I explained what can happen in the worst case (thermal runaway)...
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