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FrozenGate by Avery

803T actual power

rocketparrotlet

rocketparrotlet

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I've heard vastly varying accounts of how much power an 803T diode at 120mA will give out, and I was wondering what the real power will be. I have heard everywhere from 70mW to 120mW! I am looking for the power of the actual laser beam, using an Aixiz acrylic lens.

-Mark
 





rocketparrotlet said:
I've heard vastly varying accounts of how much power an 803T diode at 120mA will give out, and I was wondering what the real power will be.  I have heard everywhere from 70mW to 120mW!  I am looking for the power of the actual laser beam, using an Aixiz acrylic lens.  

-Mark
Click to expand...

Individual diodes vary in their efficiency. Some put out more than others. Plus some people and meters are more accurate than others. Some lenses cut down the output more than others. The only way to know for sure is to build your laser and test it.

Peace,
dave
 
I don't have a laser power meter. How could I test this? (I heard that certain members of the forums would be willing to test it for me if I paid for shipping, but I would want to send it to a respectable member so that they didn't just get a free laser.)

-Mark
 
You may be able to purchase a 803T build from a member who has a meter and is respected here on LPF.
 
I have already purchased almost all of the parts for the laser.

If it would provide any help, I purchased my diode pre-mounted in an Aixiz module from ndrew2505.

-Mark
 
Buying from ndrew means you have a good diode, bought from someone who will stand behind it:) Unfortunately that tells nothing of the exact power.. All you can do is complete the build, and if you want to know exactly what it is putting out, send it to a trusted member with a meter to have it tested.
 
Me too, I do not have a power meter but I guess it is relative to the current that drives it.
More current, more power, assuming that nothing wrong with the LD.

power = voltage x current
so, to get a estimate, multiply current and voltage and give it a huge discount for losses in heat, etc. and you will get the estimate. At least, you the the absolute ideal max power! :-)
 
LiveRock said:
Me too, I do not have a power meter but I guess it is relative to the current that drives it.
More current, more power, assuming that nothing wrong with the LD.

power = voltage x current
so, to get a estimate, multiply current and voltage and give it a huge discount for losses in heat, etc. and you will get the estimate. At least, you the the absolute ideal max power! :-)
Click to expand...


This system is almost as accurate as the "random number within a range" method.

Peace,
dave
 
daguin said:
[quote author=LiveRock link=1223254353/0#6 date=1223267781]Me too, I do not have a power meter but I guess it is relative to the current that drives it.
More current, more power, assuming that nothing wrong with the LD.

power = voltage x current
so, to get a estimate, multiply current and voltage and give it a huge discount for losses in heat, etc. and you will get the estimate. At least, you the the absolute ideal max power! :-)
Click to expand...


This system is almost as accurate as the "random number within a range" method.

Peace,
dave[/quote]

No kidding...

In a perfect system, I would be getting...540mW?

120mA*4.5V=540mW (Will the input be 4.5 volts? I'm using 3 AAA batteries.)

However, it's not a perfect system, so I would be satisfied with 20% of optimal output. Is there any better way to approximate it, like how quickly it can burn ___?

-Mark
 
You can just adjust the pot to where it's bright enough for you and lights a match within a satisfiable range and time for you.Also keeping the current in mind, not to go to high.And use an apropriate duty cycle for your host and current. :-/
 
Switch said:
You can just adjust the pot to where it's bright enough for you and lights a match within a satisfiable range and time for you.Also keeping the current in mind, not to go to high.And use an apropriate duty cycle for your host and current. :-/
Click to expand...

I know the current. I am running it at 120mA (preset by drlava). I just don't know the approximate power output. Does anyone have a graph?

-Mark
 
^There is a graph by Lava on here somewhere, titled probably something like "Blu-Ray Laser Diode Round-up". But that is still just a guesstimate. Igor has taken 30 diodes, set them al to 109mA, and got anywhere from ~70 to ~100 mW of power out of them on his meter (not exact numbers, but the range is about right). You can get an idea of it from a graph or someone else's guess, but it's still just a guess.

I would GUESS that 120mA may give you around 100mW, that's right to at least 1 significant figure ;).
 
Contact Drew... He has a meter now... maybe he tested it before he sent it to you. :)
 
Thanks everybody. I will contact Drew, and if he did not test the diode, I may consider sending it to a trusted forum member to test it for me. I'll search for that graph.

-Mark
 
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