ped
0
- Joined
- Nov 25, 2008
- Messages
- 4,889
- Points
- 113
Enough already.
Lets try and remain gentlemen, gentlemen.
Lets try and remain gentlemen, gentlemen.
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Hey CP either test it yourself, get proof or shut it. You have dont have enough data from the diode to actually prove anything.
You seem like the kind of person that would insist on 650nm even with several tests from several people. I've got a test from the mitsubishi 300mW 638, but of course that won't be good enough, so I won't even bother digging it up.
Besides, YOU are the one claiming the datasheet is wrong. The burden of proof is on YOU, not me.
OOPS :shhh:
You seem like the kind of person that would insist on 650nm even with several tests from several people. I've got a test from the mitsubishi 300mW 638, but of course that won't be good enough, so I won't even bother digging it up.
Besides, YOU are the one claiming the datasheet is wrong. The burden of proof is on YOU, not me.
OOPS :shhh:
What ever CP you know as well as I do that the data sheet is incomplete
On the OP, nobody seems to have mentioned another reason why 445nm beams appear FAR brighter per mW than 638nm. The reason is an effect called Rayleigh scatter. This effect causes wavelengths closer to UV to basically bounce off of particles in the air and to bend in the air itself like a prism. 445nm lasers are quite close to UV and 638nm is quite far thus meaning the 445nm is scattered significantly more than the 638nm making it several times brighter. Then on top of the reduced scatter effect your eyes are less sensitive to 638nm than they are to 445nm. A wavelength comparison like the OP used is actually not supposed to compare beams but instead to compare the dots. That way you are comparing purely the eye's sensitivity to the wavelength itself.
Think about it, if it was caused by the light bouncing off of dust wouldn't you see 638nm and 445nm beams in a ratio nearly identical to what you would see when the dots hit a wall? Because 638nm is much less effected by Rayleigh scatter than 445nm it passes through the air much less impeded and creates beams significantly dimmer than it would in comparison to dot brightness.
A note Rayleigh vs Mie, actually Rayleigh is the right specific type. Mie scatter is when all the wavelengths are effected equally because the particles involved are near in size to the wavelengths of light involved. Rayleigh scatter specifically effects different wavelengths differently due to the particles involved being smaller than the wavelengths involves, as is the case with lasers in air. Talking about air we are looking at micrometer sized particles where lasers are nanometer sized wavelengths which means we are indeed looking at relationships where the scatter is caused by the particles being much smaller than the wavelength.
Forget about dust. The "bluer" the wavelength, the bigger the scattering.
Red scatter little, and our eye cannot perceive it well, so overall it seems dimmer than other colors.
Do you ever had a LPC or any dvd burner laser, ham? You could easily tell by comparing...
The scattering you see is caused by Rayleigh scatter combined with larger dust particles in the air. Red(638nm) lasers are only slightly dimmer to our vision than blue(445nm) lasers so most of the reason the beams are dimmer on red lasers is because of the reduced scatter effect.
I love 1W+ 638nm lasers. They are actually powerful enough to make respectable beams at night.