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FrozenGate by Avery

14650 1600mah3.7 for alpha/envee OWNER

realista

realista

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Joined
Dec 27, 2008
Messages
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i just discovered this battery http://www.focalprice.com/14650_160...rgeable_Battery_W_PCB_2_Pack_EB142S_7069.html

it is 1.5 mc longer than 14500...... but 14500 have about 900mag rated(i think not true)....... and for an alpha series or lucent optics envee this battery should be perfect. these 2 laser cannot reach the best power output with 2 rechargeables battery 1.2volt. most.... uses... lithium energizer.( 1.6v+1.6v=3.2) but i think that these 2 high quality laserpointer can SURVIVE also at about 4 volt. if you are afraid by the more power... you must remember that this is ONLY ONE battery. so there is free space.. and... .. i DO NOT KNOW how is a trasformer.. but i think that in the free space you can put a transformer ( that regulates the voltage for example at 3.4 volt).... so.....if i think right.... the MAH of the battery (1600mah) should increase...because no all volt are used.

excuse me for my bad explanation....... !! can someone tell me if an higer voltate of the 3.7 batteru could damage a good laser diode? or if it could be possible to but in the free space a little transformer to have less vollt? an envee/alpha with this MODIFICATION.........should ENSURE long play...and higher mw output power...... ;D
 





the link sould be ok.. is the focalprice site that is down now XD.
why don't you think that lasers are made for to used with more than 3volt? using nimm battery all laser semms to be less powerful.... but i think that the diode has a tollerance. if 2x 1.6volt (2 new alkaline)=3.2...... a charget lion is at 4.2. only 1 volt more..... ok... it is no a little increase... but it isnt a DOUBLE voltage...... you seems to be a traditionalist :P also a CPU rated at 2.6 ghz.....could reaches 3.8 ghz XD....... and it was no guaranteed to operate well.. but in the 95% often it is ALL OK :)
 
Sure, be my guest. I'm just warning you, I've seen members killing their lasers in similar ways so many times before. A small rise in voltage can lead till a huge rise in current. And if not the diode dies, then the crystals might.
 
ok here is what you do

1st take out the battries and look down the compartment you should see a flathead screw type thing this is the pod of the laser
turn it just a little bit clock wise and then put your nimh battries back in

this is what i did with my laser and i was able to get lithium power but with the ability to use rechargables just by allowing more power to the laser from the less powrefull battries.... i turnd it up untill the laser started mode hopping then turnd it down a 1/2 of a turn as the pot is a 5 or 10 turn pot but i cant remember

anways hope this helps as it did mine : )
 
USING DIODES. mmmh....there is a problem.i am italian and i cannot understand all word correctly. so... DIODE... i know only a kind of diode... the laser diode(calles also pump diode i think.)..so...i must use a DIFEFRENT pump diode?... i don't thins this is what you would say me. (i try to undestand correcly...)
maybe.. for toy the diode is "the part" that can CHANGE the voltage? is this the diode you spoke?

http://i279.photobucket.com/albums/kk149/FML_01/P2040110.jpg

if i am correctly thinking....ok.. i understand that that small circuit can decrease the voltage... so it is ok to put a this thing in PLUS with a 10440 battery...so..the max volt is not 4.2 but about 3/3.2 to leave the initial native voltage of the laser pump diode. right? if my reasonind are corret..... ...mmmh... then i don't know hot made myself a diode. but... i think that this is not the correct place to learn how to made it....i MUST find an ITALIAN guide to do it eheheheh but i must find HERE the correct theory.... because there is a wonderful laser's world ... at LPF :)
 
It's ok, I'll explain further  ;)

What you need is a "silicon diode". For example diode nr. 1N5408. A diode looks like this:

1n4001.jpg


It brings down the voltage by 0.7V to 1V.
So 4.2 - 0.7 = 3.5V to the laser.

The diode has to be connected in series with the laser/battery and with the correct polarity.

It can be connected like this [smiley=smiley_down.gif] (I hope you can make this out, sorry):

 laser battery   diode   endcap

¤------(lllllllllllllllll[    [llllllll}     --l>l-- ]


Or you can do what f22warzone did, worked for him. :)
 
i give you a rep + ;) but... if the voltage is 0.7 lower.... the mah of the battery will encrease?so.. i think untill the battery puts OVER 3.5 volt...the mah is erosed SLOWLY.....(more mah)..and when the volt is under 3.5 the battery is NORMAL.....line oke without the silicon diode. but the TOTAL LIFETIME of the battery in the laser i think will increase...with the diode.... ..... right?
 
Thanks! ;)

I'm not quite following but here's the deal: Your 14650's mAh will not get lower. Instead of putting the excess energy into the laser diode and crystals, resulting in heat and shorter life, it's being put into the silicon diode (still as heat). But it wont give you more mAh either.

So long story short: your 14650's mAh will be unchanged.
 
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