The IR in a 50mW green laser

[Lol]

Thanks everyone for their posts. You all have helped me to understand this better.

Thanks again.

 

[Xplorer877]

i just bought two of these.
http://www.novalasers.com/NOVAstore/pc/viewPrd.asp?idcategory=6&idproduct=68#details

Im gunna need a DIY (Help) how to  put it in my standston11 50mW and 100mW module.

Im not going to take any chances with this IR buisness..

:-/

Same here. I wanna do this too but how dose one cut it down to size? I'm assuming it's glass right?

 

[HumanSymphony]

IR should be the least of your worries. In unfiltered lasers the IR will be something like 5-10% of the output. So a 50mW green laser would have 2.5-5mW of IR maybe, but its the 45mW of green you should worry about. We bash unfiltered lasers because they give false inflated power readings.

 

[Xplorer877]

IR should be the least of your worries. In unfiltered lasers the IR will be something like 5-10% of the output. So a 50mW green laser would have 2.5-5mW of IR maybe, but its the 45mW of green you should worry about. We bash unfiltered lasers because they give false inflated power readings.

100mW of green will use a >500mW IR diode and as you yourself said "5-10%" is not 2.5-5mW it can be up to 50mW of IR!!! An IR filter is very important because you cant see IR light. The green light is visible and therefor can be avoided.  

 

[HumanSymphony]

IR diverges quickly and will be too diffused to cause much/any damage. It also will be going in the same general path as the green so basically if you can avoid the green, then you can for the most part avoid the IR as well. A filter wont hurt though, but its probably not needed at this power.

 

[StephenOConnor]

IR diverges quickly and will be too diffused to cause much/any damage. It also will be going in the same general path as the green so basically if you can avoid the green, then you can for the most part avoid the IR as well. A filter wont hurt though, but its probably not needed at this power.

Well that answered my question that I have always wondered. But tell me this, would the IR diverging be the same as turning on a torch and pointing it at a wall? Like all the light scatters and covers a big spot?