jayrob said:

[quote author=Gazoo link=1196802322/15#24 date=1196831564]Yes but you need to put a 33 ohm 1/2 watt resistor in PARALLEL with the diode. The 33 ohm ohm resistor will absorb appx. 100ma's

Hey Gazoo, for future reference, please give the formula for this resistance...is it just the current (350) divided by the 33 ohms? Also, by 'parallel' you mean in-line on the positive lead before the LD correct? (not too sharp with electronics, I learn as I go)...

Thanks,

Jay[/quote]

Amps= sqrt(watts/ohms)

= sqrt(.5/33)

__

= sqrt(.015151515)

=.123

absorbs 123 mA

BUT

using that same formula,

if I use a 47ohm resistor,

=sqrt(.5/47)

=sqrt(.010638)

=.103

that absorbs only 103 mA as opposed to 123, and I want this diode to be powerful, so I think 47ohm 1/2 watt would be a better option.

also, you said these circuits run on only 1 CR123? I gather RCR-123 is a rechargable 3.6v version of CR123? so would 2 CR123 3.0v NON rechargables in series power this thing? thanks,

amk