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ArcticMyst Security by Avery

Quick question...

Tabish

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If I power a PHR / rkcstr driver (set at 100ma) using 2x 10440 batts (from dx).

How long before the voltage drops to where its too low for the rkcstr.

My guess:

Fully charged = 4.2 x 2 = 8.4v

phr @ 100ma uses 4.5v ??? add 2.25v the driver burns up

4.5 + 2.25 = 6.75v

8.4 - 6.75 = 1.65 (max voltage drop allowed before voltage is too low)

8.4 - 1.65 = 6.75v (lowest i should let the voltage for both bats hit)

That means 3.375 V per cell

SO BASICALLY:

The draw is 100ma. The battery is just over 300ma. (trustfire rates at 600)

How long before a 4.2v cell drops to 3.375v at that current draw and battery capacity?

Just curious because I want to put it inside jayrobs pen host but I was told 2 10440's cannot power a phr / rkcstr.

I don't mind if it runs 5min. So long as it RUNS AT ALL.
 





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cant tell you an exact time but it does take a while... if you have an lpm you can test it. the power will start to sag when the batteries get drained enough.
 

Tabish

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Ok. Thanks for the replies.

Jay, :paypal:

Eventually I'll upgrade it it with a flexdrive and a 6x or 8x.
 




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