Looking for a special equation...

[Bonnie]

The point of knowing the answer to this question isn't to be able to figure out how to round numbers... it's more of a "how can I mathematically do that" kinda' thing.

Good for you for wanting to know the "why" and the "how" of something most people take for granted. It is fun to pose a problem, then look for a solution.

BTW, have you seen this site? How a Calculator Does Division

That site also links to a page that discusses many different rounding algorithms: http://www.diycalculator.com/sp-round.shtml

 

[Deleted member 8382]

lim x->oo (2a^x) = 0 if -0.5<=a<=0.5, oo otherwise
lim x->oo (1/1+(2a^x))=1 if -0.5<=a<=0.5, else oo

because lim x->oo (1/1) = 1, regardless of x, and limit of 2a^x is 0.

...? I failed Calc 2 twice, and had to drop out... Don't think they even offer calc at the comm. college :scowl: Limits are all very interesting and everything, but simplifying integrals is where I fell on my face. That, and I couldn't understand my professor, my teaching assistant, or my tutor.

it's not 1/1, its 1/(all the other)

 

[Deleted member 8382]

lim x->oo (2a^x) = 0 if -0.5<=a<=0.5, oo otherwise
lim x->oo (1/1+(2a^x))=1 if -0.5<=a<=0.5, else oo

because lim x->oo (1/1) = 1, regardless of x, and limit of 2a^x is 0.

...? I failed Calc 2 twice, and had to drop out... Don't think they even offer calc at the comm. college :scowl: Limits are all very interesting and everything, but simplifying integrals is where I fell on my face. That, and I couldn't understand my professor, my teaching assistant, or my tutor.

it's not 1/1, its 1/(all the other)