Gazoo, according to the spec sheet keep in mind the output of the AMC7135 may vary in output from 300-380mA so you will want to test it to be sure.

If I was doing this, here are the steps I would follow.

1. Determine the actual AMC7135 output on a dummy resistive load.

2. Choose a current you would like to run the LD at.

3. Use an adjustable LM317 based current source to determine what voltage range the LD you will be using has at the desired current.

4. Take the actual current output of the AMC7135 and subtract the desired current through the LD. That's the current you will have to shunt through the resistor.

5. Determine the required resistance value by taking the LD operating voltage and divide it by the shunt current.

6. Determine the resistor wattage value by P=VI or I^2R

Example of above (made up values!!!!!!)

1. Let's say the AMC7135 came in bang on at 350mA

2. Let's say you want 200mA through the LD

3. Let's say you measured the LD's voltage to be 2.5V at 200mA

4. You will need to shunt 150mA (350-200)

5. Resistor value = 2.5V/0.15A = 16.6666667ohms

6. Resistor wattage = 2.5*0.15 = 0.375W (for short durations a 1/4W should be OK but the the design would call for a 1/2W)

All clear???