cr123a's to power driver?

[plasmaninjaa]

Im using this 1.8a driver: http://laserpointerforums.com/f39/fs-mohgasm-linear-drivers-68378.html

will 2 cr123a's in series work well to power it? they are 1800mah.
If they don't supply enough power, does anyone know what my expected power output would be to the diode?

im powering a 1.5-2w 445m diode.
thanks

(also if anyone could let me know roughly how long these batteries will run in this setup, that would be great too.)

 

[StereoBucket]

Use this simple formula to calculate resistance,amps and voltage

A=R/V
R=V/A
V=R*A

V=voltage
A=Amps
R=Resistance

Now by taking the resistance and the amps in the driver itself you can calculate the perfect voltage of the battery for the driver you want to use

 

[Cyparagon]

^Ohm's law doesn't work here. A driver is far more complex than a simple resistor.

 

[StereoBucket]

^Ohm's law doesn't work here. A driver is far more complex than a simple resistor.

yep just found it out in other topic.

 

[plasmaninjaa]

can i just get a yes or no?

 

[Cyparagon]

It should work, but it's a big strain on the batteries and you'll be lucky to get a 20 minute run-time.

 

[JuniorSG123]

just a quick check.
to increase duty cycle/run-time one can parallel another "2 CR123 in series" will help rite?
provide size isn't a concern.

 

[Cyparagon]

If you have space for 4 CR123s, then you have space for 2x18650s. 2x18650s will have substantially higher capacity than 4xcr123s.

 

[plasmaninjaa]

does anyone know what the expected output current would be for 2 cr123a's?
I don't think I want the 1.8a the driver will give out anyways so I can increase the diode lifetime....

 

[Fiddy]

yes it is designed for 2x lithium batteries in series, the driver will maintain 1.8A's until the batteries voltage fall below the Vout+the drop out voltage.