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I didn’t realise they still sell them, just had a look online. $80 for a 10mW green. Ouch!

Thanks for the offer but I am really after low powered modules for safety's sake. If I am ever looking to build another 445nm module I will definitely send you a PM first though :) What has your experience been with customs confiscating modules? Where did you order them from, and did you put up...

Hi All, I have an upcoming project and I need to source a few (1-5, whatever I can get) low powered (10-20mW preferred, 30mW max) laser modules of any visible colour (pref green/blue) within the next 3 or so weeks. TTL control is preferable but not essential. I would also prefer modules with...

Damn! I was hoping for pics. Last night I shot a moth out of the air with my 445nm. He made a smoke ring and a popping sound before plummeting to the ground.

Im running mine at about 900mA. The heatsink doesn't even make a tight fit with the body (I already had the host and jayrob had to machine it without having the exact host on hand, hence made it slightly smaller to guarantee a fit). Nevertheless, the heat issues aren't as bad as I was expecting...

I'm a civil engineer. Not related to lasers at all. I guess I can use my 445 to point things out on large construction sites in broad daylight...

I scored 34. But I am colourblind according to the ishihara tests, which is why I don't get into arguments about colours. Can you believe I worked in a hardware store mixing paint and giving out colour scheme advice for 2 years? Only a few customers noticed... and only one yelled at me for...

Jayrob, I received the lens and heatsink today. I just wanted to publically commend you on the excellent workmanship! You have a very happy customer here in Australia.

From what I've seen, the A140 diodes are in fact more powerful. The diodes that have been driven up to 1.5-2W and beyond have all come from the A140 to my knowledge. Also, if you look at the P vs I graphs over in the mW/mA thread, you'll see many of the A130 diodes have the telltale 'kink' in...

That's not something you can promise. I guess part of the reason members of this forum have strong opinions about the 1W being a first laser is because newbies don't realise just how easy it is to accidentally expose yourself or others to harmful levels of radiation. Like most, my first was a...

A quick google search shows that the ML520G71 outputs 300mW and the ML520G72 outputs 500mW. Edit: Sorry, I misread your question. I'll leave this info up though.

Re: 445nm Casio Laser Diode Compilation Thread You need to drop the input voltage to below 5.5v. From two ~4v batteries (the voltage of a 3.7v battery when fully charged) that means a 2.5v drop, which at 700mA would be dissipating 1.7W of heat in diodes. You'd be better off using the 3.7v...

Brilliant photos! You've nailed the exposure in each shot. Do you have plans to build any blue lasers?

They are indeed single mode at low powers: Blue frenzy hits the holographer too… « W’s Laserblog

Reply from DrLava: "Hi, the pot is in series with those 3 resistors, and the signal is DC. However, at startup there is a transient so you should use a twisted pair to minimize inductance. You can set up a switch between to power outputs, I would suggest using a second potentiometer that is...

Thanks Bionic-Badger. I've sent a PM to Drlava, I'll let you know his response if I get one. The reason I ask is that I already have a flexdrive spare from another build and the flexdrives have proven to be very reliable in other projects.

Another issue was brought to my attention - adding wires to this part of the circuit may make it unstable. Is anyone able to comment on that?

I've been trying to work out the resistor layout on a flexdrive V4, because with the new 445nm diodes I want to wire in a switch for high/low power. I've determined that the flexdrive sets the current based on an input resistance, which is adjusted by soldering bridges across resistors to put...

I think thats the first time Ive ever seen anyone impressed by a laser NOT popping a balloon...

It's completely arbitrary. It corresponds to half power (The square root of 1/2). This number comes up frequently because it is easier to decide on a "safety factor" to use in cases where there is no real correct answer for the "safe" value when given a "failure" value. Engineers started using...