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In another article, it says that in the next 15 years they hope to double the power and increase the rate to 6 to 10 shots per minute. Lets put that into scale...33 megajoules now, 66 megajoules then...6 times a minute is every 10 seconds...that's 6.6megajoules per second, aka 6.6 megawatts...

As long as the headphones are well-designed. Wouldn't be very useful to design noise-canceling headphones that amplify the noise, now would it? It's not a coincidence, it's part of the design. My shooting earplugs are really cool like that though: they lessen loud noises and amplify quiet...

Edited just for you.

You have to look at what lasers are designed to do. The 445nm and 405nm diodes are capable of most of the same things. If anything, 405nm is capable of more power than 445nm, all else being equal. The different we see is in design. You can have higher power or you can have lower divergence...

Incorrect. For edge-emitting diodes like we use, the physical size change of the cavity with temperature is a negligible effect. The wavelength changes with temperature because the refractive index of the materials change, not the physical size. Also, you're talking about heat as a result of...

I wouldn't be surprised if that is about 2 decimal-places off. Decimal errors happen.

<rant>I'm nitpicking, I know, but it will NOT "melt" anything on earth. And the video never says it will melt anything, good on them, bad on whoever titled that page. Because some things just do not melt at atmospheric pressure. If I stick a piece of dry ice in there, it will not melt. It...

Well you have put more into it than your first post led me to believe. Sorry for underestimating you at first, as most of the posts from newbies around here are truly from newbies, people who have no idea what they're doing. For your photodiode, you need the conversion A/W, as in how much...

You have your work cut out for you. First and foremost, even just for the CW L-I curve, you need a calibration number for each wavelength you want to measure with the photodiode. You also need to make sure your photodiode will even work for all your wavelengths (it's not uncommon to use...

Of course when you bring multiple other factors into it it's no longer a simple relationship. Bringing the astigmatism, elliptical beam, multimode behavior, and optics into it changes the equation considerably. As it should. As I said, they should keep reading, because there are indeed many...

You're mixing up some ideas. Flashlights, including LEDs, aren't coherent, so they're a whole different animal from laser diodes. The non-coherent light spreads much faster, in large part because it's not coherent. You have all kinds of other factors in play to increase the divergence, not...

A "blue diode lasers" forum and then the current blue/yellow/other forum maybe with a tweaked name. Like "Exotic solid state lasers" or something such as that.

Bad news bears. That's from a CD burner, which means it's IR. Which means it'll barely be visible, yet still powerful enough to blind you. Stay away from it if you don't know what you're doing. It'll look like a very, very weak red diode, barely a glow at all, while still being enough to...

I'm pretty sure these are little modules...as in it's a DPSS 532nm laser module (with IR diode + crystals), but miniaturized in order to fit it inside a much smaller module. No clue about quality, but they do look like those miniature modules like we've seen before.

^Good except you need more current on the low setting if you're using one of the common 445nm diodes like the a140. Those don't start lasing until around 200mA. They still turn on at lower power, but they need that much current to turn on. So you need something like 250mA as a low setting, or...

True in parallel, not true in series. That's probably the best reason to run series instead of parallel if you're going to put multiple diodes on one driver. It's a constant-current driver. In series, the total current coming out of the driver is the exact current going through both diodes...

Uuhhhhh....What? Putting 2 diodes in series means you don't double the current. If you're putting 2 diodes in series, you need double the voltage but you need the exact same current from the driver. In series, voltage adds and current is the same everywhere.

Instead of a switch that moves between paths, use a switch to activate a shunt resistance path. So that way, you have a path always there, and the parallel path just lowers your resistance. For instance, a 10ohm resistor always in place giving you a 125mA current. Then you close a switch...

Hard to say, exactly. Diodes from optical storage drives (660nm red diodes from DVD, 405nm diodes from Blu-Ray or HD-DVD) typically have a ridge width of about 1.5um, giving single lateral mode operation, since only the fundamental mode fits. The 445nm diodes we're using now have a ridge that...

Please refine this point. A neutron has no electrical charge, yet it still has an antiparticle: an antineutron, which also has no electrical charge. I'm not saying you're wrong, I'm not saying you're right, but your explanation does not answer the question. ETA: Well, I guess I'll go ahead...