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Diodes & heatsink are a bit bigger than I thought at first, the keyboard & mouse give a good size comparison (the KB is visible in the second picture as well, but hiding a bit, so it didn't quite register with me). Give it a go! Once the heatsink gets so hot that you can't touch it for a second...

200mW with a PHR? Not likely.

In the image it's shown assembled, so most likely it is.

Actually, a quick google turned up the Seoul Semiconductor P8D140: at 3.5V/350mA it delivers 210mW of 405nm light. That's not a striking difference to BR diodes as used here, but then, these are operated way outside the manufacturers "absolute maximum ratings" (and I guess better LEDs could be...

Filthy habit. Just give it up; think of all the lasers you can buy with the money you save :D

hevnsnt, that's just a voltage divider network. It's useless if you want to draw current. Better use diodes like mauswiesel said (you don't have much control over the output voltage that way) or best, a step-down converter, e.g. the drlava FlexDrive.

You use a laser if you need a laser beam. If you just want UV or near-UV light, a (non-laser) diode is much more efficient and rugged.

This should consume around 200W and maybe throw out 10k lumens. It'll make your eyes water Pictures!! EDIT: looking again, I'd get a much larger heatspreader, unless you've got a turbine to supply the cooling air flow. EDIT2: are these color or white light LEDs?

I'll believe the 5..20mm spot diameter at 50m distance when I see it :rolleyes:

Are you sure it's an extra dot, not a line through the main dot, like this: ---o--- ? This line is a well-known property of a common red laser diode, the LPC-815.

This "self-regulated" is not an actual technical term. Of course both CV and CC drivers are regulated, and they do it themselves. The shunt in analog ammeters has the same purpose as in digital ones, it's a network to split the current: one part goes through the resistor, the other through the...

Just about everything causes cancer, you just have to wait long enough...

The rated capacity assumes a discharge rate of 0.1C, which for a 500mAh battery means 50mA. The usable capacity can drop sharply at higher discharge rates. A Li-ion cell has a 4.2V charging cutoff, meaning you must not charge it to a higher voltage, otherwise it will be damaged. The voltage...

Or, it could be a PHR bluray laser which, in the honored fashion of green DPSS wattage claims, only delivers half (or less) of what is advertised...

A peltier element doesn't make sense for cooling a high-power LED, you just increase the waste heat even more. Just a copper heatspreader and a fan is enough.

It depends on where you connect the laser diode?!? A little bit more detail would be in order.

I disagree. The same current that flows through the internal resistor of the multimeter also flows through the diode. The only difference is that there will be a slight voltage drop, so the driver will have to produce a bit more output voltage as well. This is irrelevant, as keeping the current...

@Eku, not much to tell. I wanted to create a solder bridge for setting the range, it didn't quite work. I put the soldering iron aside, noticing a black speck at the tip and wiping it off, thinking it was some carbonized resin residue. Only then did I notice one of the resistors was missing...

The 9V block batteries generally cannot deliver very much current, so it might just work. The clever way to test this would be to hook up the LD, a ~20 Ohm pot, and a multimeter on a 2A (or higher) setting in series with the diode, with the pot initially at max resistance. Then slowly turn it...

Sure, why not? Also it's a good idea to use the proper measuring range. For the DMM depicted in the first post, you'd use the 200mA range for measuring the ~120mA for a PHR bluray. Note that generally using the lower current ranges requires using a different plug on the DMM than for the 10A...