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FrozenGate by Avery

.........help me and guide me please ..........

S

syed ayub basha

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SIR I AM ONE CABLE TV OPERATOR, IN MY CONTROL ROOM WE USE E D F A , TO SEND OPTICAL SIGNAL TO LONG DISTANCE. IS IT POSSIBLE ANY ONE SIT IN MY CABLE ROUTE AND CUT MY CABLE AND SEND POWER FULL LASER IN OPPOSITE DIRECTION AND THE POWER OF THAT LASER CAN DAMAGE MY E D F A ? IN MY LINE WE TRANSMITTING 1550 nm . WITH 16db. SO THEY USE SAME 1550nm WITH MORE POWER THAN 16 DB WHAT CAN HAPPEN?
 





syed ayub basha said:
SIR I AM ONE CABLE TV OPERATOR, IN MY CONTROL ROOM WE USE E D F A , TO SEND OPTICAL SIGNAL TO LONG DISTANCE. IS IT POSSIBLE ANY ONE SIT IN MY CABLE ROUTE AND CUT MY CABLE AND SEND POWER FULL LASER IN OPPOSITE DIRECTION AND THE POWER OF THAT LASER CAN DAMAGE MY E D F A ? IN MY LINE WE TRANSMITTING 1550 nm . WITH 16db. SO THEY USE SAME 1550nm WITH MORE POWER THAN 16 DB WHAT CAN HAPPEN?
Click to expand...

Sorry but I don't understand your question...:yabbem:
Perhaps you could stated your question a bit more
clearly...:undecided:

BTW.. it is called SCREAMING when you
write in all capitals on the Internet...


Jerry

You can contact us at any time on our Website: J.BAUER Electronics
 
OK sir simple i explain take one 100 m fiber optic cable and we connect both ends with different power output (in watts) optical sources. and we on both. then what happen? in both sources say example 1 is 200 mw and another is 2000 mW. now we on them what will happen ? the 200 mW sours will dead? because other side (opposite side) of that cable is very strong power it is 2000 mW. both sources are same frequency that is 1550 nm.
 
I don't understand you.

Do you ask what will happen if you point one laser at another, stronger, through an optical cable?
 
The 2000 will get to the center first because of more power and when 200 arrives the nm will reduce by 400.
 
If we care only about the energy and direction of the photon, then the electron variables can be treated as constants, meaning that it's possible to solve the system of equations. By combining these equations and using some algebraic tricks to eliminate variables, Compton arrived at the following equations (which are obviously related, since energy and wavelength are related in photons):
1 / E' - 1 / E = 1/(me c2) * (1 - cos theta)
lambda' - lambda = h/(me c) * (1 - cos theta)

The value h/(me c) is called the Compton wavelength of the electron and has a value of 0.002426 nm (or 2.426 x 10-12 m). This isn't, of course, an actual wavelength, but really a proportionality constant for the wavelength shift.
 
I think he's trying to say that two terminals or somehting are conencted with an optic fiber cable... and for some reason people on each end of the cable need to turn their light sources (lasers) at the same time and shine them through the fiber optic cable...

If i'm correct, he wants to know if wattage of terminal A (2000mw) would burn/destroy/melt terminal's B diode (200mw) OR nullify completely it's signal. (My guess is that somehow they send information thru lasers signals and his concern is that the stronger laser would destroy data sent from the lower power one.)

I guess this is what he's talking about:

If more power is launched into the cable than what the cable will accept, the excess
power is simply reflected back into the transmitter and rejected by the cable.

This is due to Stimulated Brillouin Scattering (SBS). The Power reflected back due to
SBS is at a slightly lower wavelength ( typically 0.1nm less, at 1550nm ). This SBS
back scattering is a waste and will not reach the other end of the cable. In fibre optic
systems where optical power is extremely expensive, it is imperative to ensure that all
power launched into a cable is transmitted onwards by the cable.

A few meters of ( non specialised ) Fibre optic cable can accept even 25dBm of optical
power. 1Km to 5 Kms of cable may accept upto 17dBm of optical power. However long
lengths, such as 10 Kms or more of non specialised cable can accept only 20mW or 13
dBm of optical power, beyond which SBS bounces back additional power.

Read about it here: http://www.scatmag.com/technical/techarticle-june04.pdf
 
Last edited:
hello HenryC sir you understand my problem correct. my problem is some one damaging my EDFA with this activity, he put strong source on my cable path, he cut my cable and slice one patch card to my active fiber and put in witch device i don't know , my EDFA or my fiber copulers are burn, i am asking what he put there? in my line we send 1550 nm with the power of 16 dBm.
 
I am no expert with these kind of equipment, but I've sent an e-mail to a professional, if he responds I'll tell you here ok?
 
lasersbee said:
Sorry but I don't understand your question...:yabbem:
Perhaps you could stated your question a bit more
clearly...:undecided:

BTW.. it is called SCREAMING when you
write in all capitals on the Internet...


Jerry

You can contact us at any time on our Website: J.BAUER Electronics
Click to expand...

Hey Jerry maybe he is hard of hearing. So he needs to yell:crackup:
 
Syed ayub Basha this is what the professional answered me, hope it solves your problem:

"I agree that the question could be stated a little more clearly. I am guessing from his CATV application that he has a transmitter that feeds one booster EDFA and then goes through a length of fiber to a second EDFA which boosts the signal again and then goes through a second length of fiber.

If I have the question right, then using a higher power transmitter would have little to no effect on the output of the second length of fiber that I described. That is because EDFA's operated as saturated output devices. A 15dBm EDFA will output +15dBm with a small optical input or a large optical input. General practice is to limit the input to a given EDFA to about +10dBm. So if his goal is to get more optical power at the received end, then he needs higher output EDFA's."
 
sir i am a cable operator, some of my enemy killing my control room EDFA . with his optical power. from my room lot of fibers draw in different directions. all go number of kilometers. he sit some where on that path, first he cut my cable and join with his optical device he on his device and send his optical power to my control room . here in my control room my EDFA will effect, the pump of my EDFA are damage, i am facing the problem. i asking you and forum members what he using? to damage my EDFA?
 
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