if you are using the microboost, you don't need to use the flashlight driver. Sounds like a crappy driver anyways if it's feeding the LED 2V from a 3.6V source.
Basically, microboost takes X amount of power from batteries and sends that same X amount of power (minus driver inefficiencies) to the laser diode. If the batteries don't have enough voltage to drop across the laser diode, it pulls more current so that it can boost the voltage.
If you are a math-minded person, perhaps these equations will help:
It's a given that Power = (Current)*(Volts), or
Power from the batteries (Pin, as in P-sub-in) equals power to the diode (Pout), so:
substituting for Power, we get:
To explain the variables, Vin is the voltage that the battery supplies. Vout is the Vf of the laser diode at the current that you want to run it at. You can see that if the Vout is higher than Vin, the driver will need to pull more amps from the battery than it sends through the diode.
For example, let's say you are running a diode with a Vf of 6V@1A, from a 3.6V battery.
3.6V*Iin=6V*1A
Iin will be ~1.7A for the driver to supply the 6V at 1A to the diode. That means you better make sure your battery can supply 1.7A safely for this particular situation.
These equations are for your understanding, but do not take into account driver inefficiencies.