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I've got one of those. I think I bought it directly from DTR when he no longer wanted it. Regular 1.8W blue. If you don't have a DMM, a lab-grade power supply, and some electronics background knowledge, your likelihood of fixing it is exceedingly low. We see these "my laser is broke" threads...

... but why 640 pixels?

Short answer is you need to use a different driver to the stock one, because the decoupling capacitance here will eat your pulses and ruin your rise time. A simple dropper resistor might be appropriate if your duty cycle is low. We can help you a lot better if you actually tell us what you're...

Per my last email: " Add your own open-drain signal output to the relevant gate. " If that isn't decipherable, this project isn't for you. It isn't as simple as building from a schematic, since power sources, input signals, and laser diode characteristics vary a lot. Values need to be...

Patience and context are keys. For instance: https://www.merghart.com/p/27/Two-Transistor-laser-current-source Add your own open-drain signal output to the relevant gate.

Yes. Google 2 transistor driver.

1MHz is the upper limit if built correctly. It doesn't mean you'll need or use all of the bandwidth. A 10GHz oscilloscope will measure a 2Hz signal just fine. Yeah, looks good on paper, but falls flat on its face in the real world. The scaling of the input signal, the laser diode threshold...

Since the power is relatively high, and in a visible band, you can use your eyeball (or camera) and a diffraction grating for a second opinion. Does the laser dot indeed have two wavelengths when viewed this way?

I hope this is just a side joke and you realize the use cases and design necessities aren't remotely similar.

We can help you a lot better if you actually tell us what you're trying to do, rather than throw out vague design specifications with no context.

Two orthogonal polarization filters should block nearly all light, laser or not. The reduced intensity means you can't see all of the dot since the dot intensity follows a Gaussian distribution, and the 'edges' of this distribution will no longer be perceived visually. Barring some crucial...

2 problems with your test. 6 of those diodes in series is going to be about 5.5V at this current. If that's a 1ohm shunt, that's another 1.8V. So I'm estimating you're driving a 7.3V load in an attempt to emulate a 4.5V load. Also, The lm317 current source needs almost 4V of overhead to function...

Okay, well, you just made this a lot harder on yourself. Because the pot could be as low as 100ohm or as high as 100kohm depending on the design. If you can decode what the main switching regulator is, that would help. However, if $20 is too high a price to pay to fix your mistake, that's...

You may have just broken the wiper. Desolder it and measure the three resistances between the pins.

Why are you ignoring the advice you ASKED FOR? Find another project. As to your rewording, it's tantamount to asking "can I put a toyota civic engine on a lawn mower to join F1 racing? Finding a steering wheel is the biggest problem" No, no that's not the biggest problem by a long shot and you...

You need to choose a different project. The wording of your question shows you have very little experience in this area, and I'm aware of no one else in the hobbyist arena that has managed such a feat. In other words, aim for something attainable. Learn how to 'change the oil' before you...

Correct, diodes have no problem being power-modulated. Current sources have a problem being modulated by an external impedance in series with your load. That's not the way to do this. So in short you're trying to laser-cut a vinyl record. Given the spot size of a high power blue will be very...

The whole point of a current source is its current remains unchanged, and you're trying to change it with external limitation. Not a good idea. We can help you a lot better if you actually tell us what you're trying to do, rather than post a vague design spec with no context.

Is there a reason for that design, or is it just the apple approach of "make everything else incompatible"?

I said I doubted it. Don't over-react. The fact that the emitting area is microns was justification for me to doubt. Unlike many others here, I'm happy to admit I'm wrong - that the damage area can be larger than I expected it would be. Thank you for proving otherwise, and thank you for...