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Page 4 lists exposure range as 45-100mJ/cm², so this is easily attained by varying exposure time and/or power. I don't see a relation between efficacy and wavelength though. You'd want to be sure 405nm is effective at all. There may be a better color for all I know. Why are these individuals...

From my (exceedingly limited) knowledge on lithography, the exposure is energy-dependent, not power dependent. Yes? Even with a 50% attenuation, doubling power or doubling exposure time negates this, yes?

I draw a + with a sharpie, but if you wanna risk a sticker falling off, have at 'er.

Since you've ignored my question entirely, I'll rephrase and elaborate. The lens in an existing laser printer is not opaque to violet light. It will likely have higher attenuation than that of IR light, but why have you determined this attenuation to be unacceptable? Why is your only solution...

Why is the moderate attenuation unacceptable and not remedied by higher incident power? We can help you a lot better if you actually tell us about your project rather than a tiny portion of it with seemingly random specifications.

Apostrophes aren't used for pluralizing words. Also, those keyboards are a riot.

Your 1.6ohm is already acting as current-sense. Use that. Ohm's law. Test loads are typically for verifying an unverified setup. LM317 in CC is about as opposite from unverified as you can get. On the other hand... One other use is to verify you wired things properly. On the third hand... but...

Bullshit. The voltage depends on the minimum dropout of the regulator, the battery ESR, and the forward voltage of the load. Bullshit. the best server power supplies might be over 90, but almost all of the low voltage constant current drivers are going to be 80s at best. Bullshit. The...

You've been told half a dozen times now you need current feedback, and you continue to ignore this.

I'm gonna stop you right there. because you're not. You're not processing any of the information provided to you, only bitching and moaning about Arduinos, which no one else here has mentioned but you.

The capacitor should be on the output to help prevent oscillations. A low value ceramic capacitor is ideal, something in the range of 0.1µF would be fine - the value isn't critical.

It's close enough that if you wire everything properly, it will work. It just won't regulate properly because the voltage of the 9V battery will sag to under the minimum dropout of the regulator. Either you use a higher current voltage source, or your driver is no better than a simple resistor.

Excellent! Now piss off.

Although it was rather harsh (even by my standards ) ;), there's some good info there. You would do well to read it.

I see. I think you have minimal to gain by trying to insert it further. There is a sufficient level of metal-to-metal contact, and even if this was 40 times the power claimed, it would have no problems dissipating the heat as-is.

I try not to brag, and programming has precisely nothing to do with analog circuitry design, but since YOU brought it up, I actually program and repair literal supercomputers. I'm at the NOAA/WCOSS-II installation as I type this. So go fuck yourself and learn some basic electronics before you...

Okay, I thought you just typo'd the lm317. The LM311 makes even less sense in this context because it's a comparator. No one uses a comparator for current feedback. You're demonizing an idea that no one here utilizes, proving once again you don't know what's going on. Driving a diode with a...

You need a current sense feature, dunkelheit. Thermal runaway is a real concern. Also, any variation in your supply voltage translates to a variation in your output. This is not acceptable for driving sensitive devices like laser diodes. A PWM signal from a microcontroller is lazy, expensive...

So where you've labeled 12, is it 12 or not? If so, it will fit into a 12mm hole. If not, you've either labeled something wrong, or the precision of your measurements isn't high enough (which is where a caliper would help) Or perhaps I'm just reading the drawing wrong.