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ArcticMyst Security by Avery

Physics Coursework On Lenses- Please help me!

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Jan 21, 2010
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Alright. I'm doing a peice of Physics Coursework for my A-Level. It's worth 40/300 marks so it's quite important and I need some help, and probably will throughout the process of writing it so I'm starting this thread.

Every time I encounter a problem I'll post it in here and hope (possibly in vain, but hopefully not) that someone will come to my aid. Alternatively, If there's anyone nice enough to let me PM them when I run into trouble that would be much appreciated.

The coursework is mainly on Quality of Measurement and our ability to assess error margins & such. Nasty stuff. But we've got to show off our knowledge of Physics at the same time. Mine is on using three different methods to find the focal point of a lens. If anyone's really interested I'll post more info.

My first problem is that i know the equation 1/F = 1/V - 1/U when V is the Image distance (distance from the lens to the screen) and U is the Object distance (distance from the object to the lens), but I don't understand WHY. My textbook is pretty much useless.

So can anyone explain why 1/F = 1/V - 1/U?

Thanks in advance. You're all really helpful and I'll repay one day sooner or later if i can. Maybe by donating, or maybe by helping to aid the collective knowledge contained on the forum.




tl;dr Why does 1/F = 1/V - 1/U?
 
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Wow... reading through all that I realise I talk a lot of crap. Lol...
 
D

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Optics Bench

Lurk a bit there. I can't explain you why just as I can't explain you why p=ma (is the Newton second law spelled like this in English?), they are just "laws" ;)
 

JIMS19

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Dear JaiNobe,I learned in school D=1/f. Thats diopters or lens power,thats D and the inverse of the focal length f divided by 1.Example a 4 meter focal length divided into 1=0.25 Dioptric power of the lens or a "quarter diopter lens"- I hope I helped some.
 




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