Welcome to Laser Pointer Forums - discuss green laser pointers, blue laser pointers, and all types of lasers

LPF Donation via Stripe | LPF Donation - Other Methods

Links below open in new window

ArcticMyst Security by Avery

Need Help for build my laser pointer

H

Haiyder

0
Joined
Nov 16, 2014
Messages
8
Points
0
Hello comunity of Laser Pointer Forums.
First of all, I would like say I'm French. And I come to you because you are the only ones who can help me. And I'm sorry in advance for any spelling mistakes.

I have a laser diode blueray of the PS3. The reference is KEM-450-DAA. The diode have 3 pins. On the diode i can read "OP0401596284" but i can not find a datasheet of this reference.
I would like to make a laser pointer with this diode. For this I have 6 battery rechargeable 4: AAA Ni-MH 700mAh 1.2V and 2: AAA Ni-MH 500 mAh 1.2V.

I want to build electrical system with pushbutton, resistor, battery and the diode.

My questions are: -What resistor i can use ?
-How I can use battery?
-And What i can add in my electrical system?


Thank you in advance for answer me.
 





ChaosLord

ChaosLord

0
Joined
Feb 18, 2013
Messages
744
Points
28
Those batteries won't cut it. You shouldn't mix the 700mAh and 500mAh, and just four Ni-mh will not have enough voltage. Even if you had six, their current draw capabilities are not the best.

You will also need a proper constant current driver, a resistor isn't enough. Search for "CC-boost" or "benboost" in the search bar at the bottom of the page.
 
H

Haiyder

0
Joined
Nov 16, 2014
Messages
8
Points
0
Thank you for the information about batteries.
What kind of batteries can I use for a laser pointer if possible rechargeable? And "CC-boost" and "benboost" I don't understand very well. What this?

And the YT videos are not always understandable
 
The Lightning Stalker

The Lightning Stalker

0
Joined
Aug 14, 2013
Messages
2,655
Points
63
The pinout is most likely the same as a PHR
or GGW. It could also have the middle pin
as negative like a LPC. The + pin will
always be the same. If it's a PHR, it is
good for about 125mA. Otherwise, only
40mA. In that case, it's not enough to
light a match or burn anything, but still
enough to do fluorescence and GITD.
 
D

Deathunter88

0
Joined
Oct 20, 2014
Messages
21
Points
0
Hello Haiyder,
First of all I would suggest you first make a post introducing yourself. Second I would like to say that you should do a bit more research on how lasers work before asking for help. A simple understanding of how drivers work, why they are important should suffice. Also there is a great function in the forums called the LPF search. It is much better than the normal search function. I would also suggest reading all of the stickies in each of the sections. That said, welcome to the forums. :)
 
H

Haiyder

0
Joined
Nov 16, 2014
Messages
8
Points
0
The Lightning Stalker thank you. For the pinout, I have a picture for the negative and positive pin. So I need above 40mA to burn anything ?
Deathunter88: I do not think long stay that is why i make a post introducing myself in first time. still, thanks for the welcome :)
 
The Lightning Stalker

The Lightning Stalker

0
Joined
Aug 14, 2013
Messages
2,655
Points
63
Haiyder said:
The Lightning Stalker thank you. For the pinout, I have a picture for the negative and positive pin. So I need above 40mA to burn anything ?
Click to expand...

Yes. If your goal is burning, then I would
shoot for 125mA. That will burn a little.
If it doesn't work and the diode fails,
then it wasn't meant to be. 6X and above
are much better for burning. If you want a
really nice single mode burner, then go for
a S06J or even better a BDR.

In any case, wear laser safety glasses
when focused burning close up.
 
Last edited:
H

Haiyder

0
Joined
Nov 16, 2014
Messages
8
Points
0
I would take the 125ma but I'm a novice in electrical. And I don't know how make this system. :undecided:
My goal is not realy burn everything I see. I'm not crazy :)
I would like make laser pointer that burn a little.

With any laser, I pay attention. And I take any protection.
 
Eudaimonium

Eudaimonium

0
Joined
Feb 5, 2008
Messages
6,252
Points
83
Unfortunately, you cannot make a laser that burns with a diode taken from PS3 console.

It will give off maximum of 20 mW if you are lucky, and it should be driven at very low currents (25mA if I remember correctly). You would need at least 50mW or so, of output power to make the laser burn anything.

If you are still interested in building it, here is a simple schematic for a linear driver that could help you:


And here is a schematic how to use a "test load", that is, how to make something that behaves like a laser diode, and attach it to the driver so that you can measure the current and make sure it's good before you use your real laser diode.



With this driver, you will need a power source between 7 and 12 volts. I recommend playing around with various AC adapters you might have, or buying some lithium ion batteries from dealextreme.com.
 
H

Haiyder

0
Joined
Nov 16, 2014
Messages
8
Points
0
Thanks Eudaimonium for the shematic is all I need. :)
Not to have fasse, the component C1 si a contactor?
The LM317 is a reductor of current?
The resistor is 125/current for exemple
125/7v = 17,8 ohm?
Thank again for help me :)
 
Eudaimonium

Eudaimonium

0
Joined
Feb 5, 2008
Messages
6,252
Points
83
Haiyder said:
Thanks Eudaimonium for the shematic is all I need. :)
Not to have fasse, the component C1 si a contactor?
The LM317 is a reductor of current?
The resistor is 125/current for exemple
125/7v = 17,8 ohm?
Thank again for help me :)
Click to expand...

Component C1 is "capacitor". It is optional. You can build the circuit without it, if you wish.

LM317 is current regulator. It is a chip that only lets correct amount of current through.

Resistor is used to set that current.

If your desired current is 20 mA (milliamperes), that is 0.02 Amperes.

You need 1.25 / 0.02 = 62 Ohms.

Formula also works the other way around:
If you have, example, 70 ohms resistor, the current would be:
1.25 / 70 = 0.017 A, (or 17 mA).

Or 60 Ohms resistor:
1.25 / 60 = 0.0208 A, or 20.8 mA.

This only works with this specific chip, LM317, and it's variant, LM1117. You can find those chips on eBay for VERY cheap.

Remember:
Amperes = Current
Volts = Voltage
Watts = Power

Also, it will help if you learn "Ohm's law".
 
H

Haiyder

0
Joined
Nov 16, 2014
Messages
8
Points
0
Thank again :)
I take the component C1 if i have this. The LM317 I'm not sure to have, otherwise I'll buy.
For the resistor I'll wait to have batteries. For the remainder, I look if I have otherwise I buy.

I come to you when I have new.
 
Eudaimonium

Eudaimonium

0
Joined
Feb 5, 2008
Messages
6,252
Points
83
Haiyder said:
Thank again :)
I take the component C1 if i have this. The LM317 I'm not sure to have, otherwise I'll buy.
For the resistor I'll wait to have batteries. For the remainder, I look if I have otherwise I buy.

I come to you when I have new.
Click to expand...

If you need to buy components, always use ebay. It's very cheap.

This is ten pieces LM317 for $1.70
10pcs LM317 LM317T 1 2 3 7V to 220 Adjustable Voltage Regulator | eBay

This is fifty 12ohm resistors for a dollar (search for any values you want):
50 x Resistors 12 Ohm Ohms 1 4W 0 25W 5 Carbon Film | eBay

This is 25 rectifier diodes for a dollar:
Portable 25pcs 1N4007 1A 1000V Rectifier Diode do 41 Tape Tool | eBay
 
You must log in or register to reply here.




Top