Everyone,

My new Survival Laser laser is a lot of fun. Soon, I will test the output and report the results here.

The expected output is 2W. So, I did some quick checking of the battery voltage and current. My two batteries measured 7.81V. The current measured 1.7A.

Since P=VI, Watts=7.81V X 1.7A = 13.277W.

I was hoping for 50% efficiency, but that is not going to happen.

Does the laser really loose that much energy due to heat and resistance (which is turned to heat)?

P.S. I searched for that information, but did not find the answer. I must have used the wrong search terms.

My new Survival Laser laser is a lot of fun. Soon, I will test the output and report the results here.

The expected output is 2W. So, I did some quick checking of the battery voltage and current. My two batteries measured 7.81V. The current measured 1.7A.

Since P=VI, Watts=7.81V X 1.7A = 13.277W.

*, the efficiency is 2W/13.277W = 15.06% efficiency. :cryyy:***Assuming a 2W output**I was hoping for 50% efficiency, but that is not going to happen.

Does the laser really loose that much energy due to heat and resistance (which is turned to heat)?

**Am I missing something?**P.S. I searched for that information, but did not find the answer. I must have used the wrong search terms.

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