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ArcticMyst Security by Avery

$5 buck driver on ebay






Joined
Jun 19, 2010
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That's a nice little find with some real potential!

If you pick one up, being in Australia, let us know what you find. They may be good for projector builds or like you said larger, perhaps multiple diode builds.
 

jakeGT

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Oct 29, 2010
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8-45V? So dual cell builds will only keep it running for a few minutes right? So it would have to be a large build fo sho
 
Joined
Sep 12, 2007
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Here's a 3.2V+ model. It looks the same, though. Soldering will be required to convert it to constant-current, and depending on the Vref of the system, the sense resistor might ruin the efficiency.
 
Joined
May 31, 2009
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The problem I see is that it is a voltage regulator, not a adjustable current regulator, if I'm not wrong.

If you want a voltage and adjustable current regulator, look at like this for example, or similar.


http://cgi.ebay.es/DC-Power-Supply-...824?pt=LH_DefaultDomain_2&hash=item3cb6ad07e8


I bought several and they work well.

Those are nice! I'm gonna pick some of those up for testing.

@OP 22uf caps? That output is gonna be horrible! It won't filter out the ripples at all.
 

LaZeRz

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yeh, well, its probably more suited to LED's or something... lol

Just putting it out there, I was about to go to bed and I couldnt be bothered looking around on ebay anymore. haha
 
Joined
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The equation I have for filtering of a full-wave rectifier in my notes here is

Vripple = Vp/(2fCR)

Where Vripple is the peak-peak ripple voltage, Vp is the peak input voltage, f is the drive frequency, C is the capacitance, and R is the resistance of the load. This means that for a given voltage, the ripple voltage goes down when you increase either the load resistance, the capacitance, or the frequency. The frequency on these switching drivers is VERY high compared with say the 60Hz from the wall. This means that much lower capacitance is needed to keep the ripple voltage to a minimum.
 




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