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how to make analog modulation ?

djLscatt

djLscatt

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hey guy
I want to buy this module

RGB 800mW Laser Module White Beam Combined BY638NM 532nm 450NMANALOGO Modulation | eBay

i don't think I known how to make an analog modulation.
I thought I could use 3 1k pots , 3 2.5k resistances in parallel , 3 237ohms resistances and 2 18650 batteries to make a 0 5v variable power supply.
i know I won't go under v1.25 with lm 317.
34hvz1f.jpg



2pqoyt5.jpg



what is your advice ?

:thanks:
 





T

Things

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Just use a potentiometer set up as a resistive divider, a 10K pot will work.
 
123splat

123splat

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What does that have to do with modulation? Ya gonna twist the wiper on the pot to modulate?
 
ARG

ARG

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So in other words you want a 0-5V adjustable power source?

You could also make a PWM signal with a 555 timer to adjust the power.b
 
djLscatt

djLscatt

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T

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The module already is analog modulation, you don't need another driver for it. Just use a potentiometer as a resistive divider like I said.
 
djLscatt

djLscatt

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Things said:
The module already is analog modulation, you don't need another driver for it. Just use a potentiometer as a resistive divider like I said.
Click to expand...

I'm understand well I just have to go that


xbe2v6.jpg



it is simpler than I was thinking, I thought I would use an 0-5v external power source for the modulation

:thanks:
 
T

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Like this image here:

potentiometer.jpg


Attach the red wire to 5V, the blue wire to the analog modulation + input, and the black wire to negative, and also the analog modulation negative to negative too. Then you will get 0-5V out of the middle potentiometer pin.
 
djLscatt

djLscatt

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Things said:
Like this image here:

potentiometer.jpg


Attach the red wire to 5V, the blue wire to the analog modulation + input, and the black wire to negative, and also the analog modulation negative to negative too. Then you will get 0-5V out of the middle potentiometer pin.
Click to expand...


if i understood fine I'll do that:

35n0opw.jpg


but I haven't bought the module yet so i don't know where is the 5v
 
T

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You can use a resistive divider to get the 5V. The laser module is 12V input power, so:

Resistive_divider.png


Connect Vin to the laser power source (12V), make R1 10Kohms, R2, 6.8Kohms, and then Vout is your 5V for the potentiometers.
 
djLscatt

djLscatt

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Things said:
You can use a resistive divider to get the 5V. The laser module is 12V input power, so:

Resistive_divider.png


Connect Vin to the laser power source (12V), make R1 10Kohms, R2, 6.8Kohms, and then Vout is your 5V for the potentiometers.
Click to expand...

as members of this forum , i use this module as portable.
I use 2x26650 batteries so I use R1 10Kohms and R2 15Kohms

5.040V= 8,4*15000/10000+15000
:thanks:
 
paulkruger

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If that is same as my W800 there are three fan outputs which I believe are 5volt. Only two fans uses so there is a vacant 5v output jack.

Double check...I did not measure but manufacturer says the fans are 5 VDC.
 
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