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ArcticMyst Security by Avery

Looking for a special equation...

B

Bonnie

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Nov 12, 2010
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pianoman2011 said:
The point of knowing the answer to this question isn't to be able to figure out how to round numbers... it's more of a "how can I mathematically do that" kinda' thing.
Click to expand...

Good for you for wanting to know the "why" and the "how" of something most people take for granted. It is fun to pose a problem, then look for a solution.

BTW, have you seen this site? How a Calculator Does Division

That site also links to a page that discusses many different rounding algorithms: http://www.diycalculator.com/sp-round.shtml
 
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D

Deleted member 8382

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BShanahan14rulz said:
lim x->oo (2a^x) = 0 if -0.5<=a<=0.5, oo otherwise
lim x->oo (1/1+(2a^x))=1 if -0.5<=a<=0.5, else oo

because lim x->oo (1/1) = 1, regardless of x, and limit of 2a^x is 0.

...? I failed Calc 2 twice, and had to drop out... Don't think they even offer calc at the comm. college :scowl: Limits are all very interesting and everything, but simplifying integrals is where I fell on my face. That, and I couldn't understand my professor, my teaching assistant, or my tutor.
Click to expand...

it's not 1/1, its 1/(all the other) ;)
 
D

Deleted member 8382

Guest
BShanahan14rulz said:
lim x->oo (2a^x) = 0 if -0.5<=a<=0.5, oo otherwise
lim x->oo (1/1+(2a^x))=1 if -0.5<=a<=0.5, else oo

because lim x->oo (1/1) = 1, regardless of x, and limit of 2a^x is 0.

...? I failed Calc 2 twice, and had to drop out... Don't think they even offer calc at the comm. college :scowl: Limits are all very interesting and everything, but simplifying integrals is where I fell on my face. That, and I couldn't understand my professor, my teaching assistant, or my tutor.
Click to expand...

it's not 1/1, its 1/(all the other) ;)
 
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