May 26, 2009 #1 L laserlover 0 Joined Jun 17, 2008 Messages 586 Points 0 how do you convert y= 50 times (1/(5e^(-.202x))) (e being 2.718281828) to y=AB^x form? thank you sooo much!
how do you convert y= 50 times (1/(5e^(-.202x))) (e being 2.718281828) to y=AB^x form? thank you sooo much!
May 26, 2009 #2 L laserlover 0 Joined Jun 17, 2008 Messages 586 Points 0 here is a picture http://i307.photobucket.com/albums/nn289/travisloveslasers/mathquestion.jpg?t=1243306979
here is a picture http://i307.photobucket.com/albums/nn289/travisloveslasers/mathquestion.jpg?t=1243306979
May 26, 2009 #4 N nikokapo 1 Joined Dec 26, 2007 Messages 6,129 Points 0 Easy, A = 50; B = (1/5)*e^(0.202*x) What you need to do there is just use the minus on the -0.202*x to move it up. I don't know if that's the answer you needed. You can't work any further with this if you want the result with Y = something. Let me know if I'm right or I'll look more into it. EDIT: 1/5 * 50 = 10; Therefore A = 10 ^ B = e^(0.202*x)
Easy, A = 50; B = (1/5)*e^(0.202*x) What you need to do there is just use the minus on the -0.202*x to move it up. I don't know if that's the answer you needed. You can't work any further with this if you want the result with Y = something. Let me know if I'm right or I'll look more into it. EDIT: 1/5 * 50 = 10; Therefore A = 10 ^ B = e^(0.202*x)
May 26, 2009 #5 L laserlover 0 Joined Jun 17, 2008 Messages 586 Points 0 thanks nikokapo! i needed that badly, lol
May 26, 2009 #6 N nikokapo 1 Joined Dec 26, 2007 Messages 6,129 Points 0 No problem, anything else I'm here