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Stripping a benq dw1620

Eudaimonium

Eudaimonium

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No, where you pointed the " - diode" , positive of diodes goes there, and negative of laser diode goes on the other side of the board.

Also, crappy or not, camera can always take better photo than this. Move the camera away from the object and them use zoom on it. Or just take photo as is, and crop it in PC software.
 





Userro

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Eudaimonium said:
Both 1 and 2 are same point, you can see them connected with a trace.

Connect your battery positive there, battery negative to 3, laser diode positive to 4, and laser diode negative to, presumably pad on the other side of the PCB.
Click to expand...

Eudaimonium said:
No, where you pointed the " - diode" , positive of diodes goes there, and negative of laser diode goes on the other side of the board.

Also, crappy or not, camera can always take better photo than this. Move the camera away from the object and them use zoom on it. Or just take photo as is, and crop it in PC software.
Click to expand...

It seems to me that those two posts contradict themself about the diode's connections, or maybe I cannot understand what you're trying to explane.
 
Eudaimonium

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It seems that indeed, they do contradict themselves. Sorry but this is older thread and I've forgotten what this is all about.

If I have explained in detail what you need to do before (first post you quoted), then why are you asking again?
 
Userro

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Eudaimonium said:
It seems that indeed, they do contradict themselves. Sorry but this is older thread and I've forgotten what this is all about.

If I have explained in detail what you need to do before (first post you quoted), then why are you asking again?
Click to expand...

just to be sure, I've never posted a pic of the other side of the board, lot of time has passed and I don't want to ruin my limited resources.
Doesn't sound strange to me.
 
Fiddy

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this should do the trick matey :)

13110717000.jpg
 
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Userro

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ok, thanks, so the first post was wrong, nice to know before doing any damage :)
 
Eudaimonium

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Huh seems I was completely wrong :p I always figured the pads on the board would correspond to the red diode's pin arrangement and polarities (i.e. the sole pad on other side would be negative connection).

My bad :)
 
Userro

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ok, done with the linking, about the measurement, where should I do it? the picture says on both side of the resistor, should I do it on the resistor or on the diode on its right? Maybe it's the same, I don't know. I tried with the 200m scale and the value oscillate between 107 and 109 mV, I don't know if it's right, is it a plausible value? I put the red jack in the plug "A V Hz H" and the black one in the "COM plug" (I think this is right), there is a third plug named 10A. also I think the measurement should be done with the mm setted to DC ando no AC, I'm I right? there's also a L/C button but I don't know it's meaning.
 
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Eudaimonium

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Yes, the measurement appears correct, fluctations of few mA are normal. You are measuring right, you should measure in mV range unless you are trying to set your driver to more than 200mA range.

What current are you aiming at?

P.S. Only use 10A plug when you are using 10A measuring range. Using it any other way can fry a fuse in your DMM, or your DMM.
 
Userro

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I don't know, I mean, I'm supposed to use AA batteries? Maybe would be nice to install a plug for the use of ac. I would like to obtain maximum power from the diode of course.
 
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Fiddy

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it doesnt matter if you get the polarity wrong of the meter, it willjust show -200mA or (+)200mA.

Make sure your meter is on DC not AC.
 
Userro

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all connection and measurements done, I just need to set the pad and wire the diode.
Just how should I set the pad?
 
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