A questions

As anyone knows about power attenuation per meter? burning power loss and how much? exist a measurement?
Obviously the climatological conditions of cold and heat affected guess not?

My aim is to know, Example 5 watts to 10 meters = 4,50 final watts of power (500mw lost)



Sorry for my english and if this question is already been asked

I'll go to sleep now and I always leave strange doubts jajajajja :crackup:


edit to put it in Spanish too

¿Existe la medición de la perdida de poder del laser / por metro? o cuanto se supone que es

obviamente los efectos del clima como el frio y el calor también afectarán a la potencia final no es así?

Mi objetivo a conocer es por ejemplo 5 watts a 10 metros = 4,50 watios de potencia finales (500mw perdidos)

Sera mejor que escribas la pregunta en español porque no se entiende que quieres decir...
Saludos

It depends on atmospheric conditions, but unless there's fog, mist, dust, or other particulates in the air, you can approximate losses to be zero.

Also depends on wavelength .. anyway in meters range, and common conditions .. there are no losses due the medium. There is power density decrease due divergence, which is major limiting factor for burning.

thanks for answering

Did so there is no loss by distance o.0?

DrSid said:

Also depends on wavelength .. anyway in meters range, and common conditions .. there are no losses due the medium. There is power density decrease due divergence, which is major limiting factor for burning.

Click to expand...

this was what I also wanted to know

loses much power burned by distance?

For common practical purposes (unless you shoot down ballistic missiles), there is no absorption loss.
As for divergence loss .. laser beam focused to infinity is always a cone. Very narrow cone .. but cone none the less. It is problem of light diffraction, and nothing can be done about it. Anyway lasers are such perfect light sources, that they actually reach this limit. Common light sources are even much worse.
Beam increases diameter in practically linear fashion. Or, we can say, it has a divergence angle. For common pointers it is about 1 milliradian (mRad). Which means that at 1000m the spot size will be 1m in diameter (well more exactly it is distance * tan(divergence), but for small angles it's the same thing).
Burning depends mostly on power density .. power / spot area .. and spot area is more or less pi * spot size^2. So while spot size increases in linear fashion, power density decreases with quadratic fashion.
With common pointer you can expect burning capabilities to drop real fast. At 10 meters the power will be a lot decreased. At 100m you won't burn a thing.
Divergence of laser is defined by output aperture and wavelength. It's more or less divergence = wavelength/aperture. So if you want to improve divergence, you need large output aperture .. like that ABL in my avatar picture .. it has 2m output aperture is designed to shoot down missiles at few hundred km. For pointers you can sometimes but beam expander which does just that .. but optics tends to be rather expansive.
Some lasers have additional problems. For example very popular 445nm lasers have divergence different in X and Y axis (because it's multimode laser). So with spherical lens it's impossible to collimate both X and Y axis at the same time. This results in even lower divergence.

dude solved

thanks DrSid rep added