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Old 02-14-2011, 11:24 PM #1
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Default Test load question

I am building my own test load using 1 1ohm 10 watt resistor and 6 1N5404 diodes. My question is why must I wire the output of my driver differently between the 1N5404 diodes if I am using blue or red. All i want to test is the mA the driver is outputting.


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Old 02-15-2011, 12:50 AM #2
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Default Re: Test load question

blue and red have diff erent voltage drop
blue = 4-4.5v
red = ~3v
but i think you can use 4 * 1N5404 for a blue
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Old 02-15-2011, 12:57 AM #3
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Default Re: Test load question

Thanks. Im still a little bit confused. everyone told me to use 6?
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Originally Posted by bluuray View Post
blue and red have diff erent voltage drop
blue = 4-4.5v
red = ~3v
but i think you can use 4 * 1N5404 for a blue
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Old 02-15-2011, 01:55 AM #4
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Default Re: Test load question

I think you'd use 6 for violet (405nm)

Can't the voltage drop for that approach 6V ?
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Old 02-15-2011, 02:04 AM #5
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Default Re: Test load question

What seems to work for me is:
4 diodes for RED
5 diodes for BLUE (445)
6 diodes for VIOLET (405)
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Old 02-15-2011, 03:04 PM #6
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Default Re: Test load question

Rectifiers generally drop 0.6 to 0.7V, not 1V.
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Old 02-15-2011, 03:48 PM #7
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Default Re: Test load question

^ at 100mA or less ..... diodes dropout depends from the current, 1n400x, as example, are 0,75V under 100mA, but around 1V at 800 / 900mA ..... also 1N540x serie have a curve depending from the current, as any other silicon diodes.
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