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Scheme for 2W m140 diode driver

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Nov 29, 2014
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Hello Guys, I just joined LPF.

I ordered 2W m140 with G2 lens(1.8 amp suggested)

Now, I need a driver scheme.I have tons of resistors, variable resistors, regulators and capacitors.

I have questions about diode's working principal
1-) Can I use 2 of LM317T regulator to give diode 5V and 3amps? Will diode die @5V 3Amps?
2-) When I give 5V 3 amps, will diode comsume 1.8amps or consume 3amps and die?
3-) Can I reduce 3amps to 1.8amps from regulator"S" output?If the answer is yes, which components can do it?
4-) Will 1.5 amps enough for m140, will diode be stable?
5-) Can I use 2 of L7805 regulator instead of LM317T?

Please help me at this sitation.Sorry for bad English.Thank you guys.
 





rhd

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1) Yes, that will toast your diode
2) You don't hold both voltage and current constant it's one or the other. Again though, 3A = toast, and relying on constant voltage of 5V is a bad strategy too.
3) This doesn't make any sense.
4) A clean regulated constant current of 1.5A from a proper constant current driver (like an xdrive) would be fine.
5) No. The 7805 isn't a constant current regulator.

I don't think you've done enough research to be building your own driver. There are major concepts that you're missing here.
 

rhd

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Will be 2 x 18650, 3400 MAh i guess.MAh can change.

Thanks.

Then no, LM317 is not an appropriate option for an M140 diode. Too much voltage drop.

I recommend a buck driver.
 
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Then no, LM317 is not an appropriate option for an M140 diode. Too much voltage drop.

I recommend a buck driver.

How can i make a driver like x-drive?I can use 3 x 18650 if it will be fine and I can use capacitors too.
 
Last edited:

rhd

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How can i make a driver like x-drive?I can use 3 x 18650 if it will be fine and I can use capacitors too.

No disrespect intended, but based on your initial questions, I think building a switching buck or boost is a couple levels above where you're at right now. But if you are intent on building your own, give this a read:

www.linear.com/docs/4120

Linear drivers have their place, but that place isn't driving M140s. 3x lithiums would imply 12+ Watts of heat from your driver at full charge, and 2x isn't enough to clear the vdrop once voltage sags.

Go with a switching buck or boost. That's my recommendation. That's how people drive them reliably. No need to try and reinvent the wheel.
 
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Nov 29, 2014
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No disrespect intended, but based on your initial questions, I think building a switching buck or boost is a couple levels above where you're at right now. But if you are intent on building your own, give this a read:

www.linear.com/docs/4120

Linear drivers have their place, but that place isn't driving M140s. 3x lithiums would imply 12+ Watts of heat from your driver at full charge, and 2x isn't enough to clear the vdrop once voltage sags.

Go with a switching buck or boost. That's my recommendation. That's how people drive them reliably. No need to try and reinvent the wheel.

I am really appreciated, but this text is just too much for my english."when you are not busy and can't find something to do" pls send me a parts list and scheme, I'll buy them.I am waiting for hearing from you soon.

Thanks Sir
 

rhd

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I am really appreciated, but this text is just too much for my english."when you are not busy and can't find something to do" pls send me a parts list and scheme, I'll buy them.I am waiting for hearing from you soon.

Thanks Sir

The part you are looking for is called:

- X-drive V6 1.8A
 




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