Powering a 405nm 12X with Groove2 or RKCST

• Jun 6, 2011

• #1

yobresal

0

Joined

Nov 5, 2007

Messages

4,919

Points

83

I know I have done this before. Sure it easy with 2 lithium ions, but what about 3? can I use either of them with a Voltage input of 12.6V (on full charge) Please god give me the answers.

 

Last edited: Jun 7, 2011

• Jun 6, 2011

• #2

Ra1nfade

0

Joined

Jan 27, 2011

Messages

701

Points

0

For Your Rkcstr questions,

http://rkcstr.googlepages.com/MDADJv2instructions.pdf


For your Groove2 questions

http://modwerx.com/Groove2_manual.pdf

:beer:

Couldnt access them on my work computer but I think both of these tap out at close to 12V input

 

Last edited: Jun 6, 2011

• Jun 7, 2011

• #3

yobresal

0

Joined

Nov 5, 2007

Messages

4,919

Points

83

Looks like I can get the rkcstr up to 15V so that will work but it will only be 440mA. I really want to get 550mA and most Groove drives get up that high. What I need to know is the type/name of that "diode" to be used to reduce the voltage and where to install it.

 

Last edited: Jun 7, 2011

• Jun 7, 2011

• #4

A

anselm

0

Joined

Nov 22, 2010

Messages

2,448

Points

0

Just remember that all excess voltage will be burned off as heat by the driver.
So if you're only using 6V for the diode, the other ~6V are waste heat at the driver.
You will need proper heatsinking, is all.
I'm sure you knew that, though, just reminding you.

 

• Jun 7, 2011

• #5

Ra1nfade

0

Joined

Jan 27, 2011

Messages

701

Points

0

Dual Rckstr's possibly... Just wondering Yob why all the voltage?


Flying Cat^^^

 

Last edited: Jun 7, 2011

• Jun 7, 2011

• #6

yobresal

0

Joined

Nov 5, 2007

Messages

4,919

Points

83

I figured it out guys. I actually have the "diode" I need in my parts bin. I just need to solder it in series before the driver to bring the voltage down.
I'm building a 12X in a 3405 host and want to use 3 10440 batteries. Hence the issue. Thanks guys!

 

• Jun 7, 2011

• #7

lazeerer

0

Joined

May 25, 2010

Messages

3,655

Points

0

If you can fit more then 1 diode before the driver that would be a plus. This will droop the voltage alot more and keep your laser driver cool witch will give you more on time.

Why not just use 2x 10440 Rather then 3. Just solder a dummy wire across one of the battery channels to act as the 3rd battery.

Oh and the name of the diodes you can use are "1N4001". There are other diodes out there but that is one of your common ones that you can pick up locally like at radio shack.

 

Last edited: Jun 7, 2011

• Jun 7, 2011

• #8

Ra1nfade

0

Joined

Jan 27, 2011

Messages

701

Points

0

Ok I see what your doing now. You could always wire the holder to run in parallel.

 

• Jun 7, 2011

• #9

lazeerer

0

Joined

May 25, 2010

Messages

3,655

Points

0

^ That would not work. Its not enough voltage.

 

• Jun 7, 2011

• #10

Ra1nfade

0

Joined

Jan 27, 2011

Messages

701

Points

0

yup my bad

 

• Jun 7, 2011

• #11

yobresal

0

Joined

Nov 5, 2007

Messages

4,919

Points

83

Yeah there are a few options. I don't want to use a boost so no parallel batteries (or AAA) I don't want to use 2 cells because The current will sag as the voltage drains. I have the part I needed all along so I will just solder it in. How much does it drop the voltage?

 

• Jun 7, 2011

• #12

Ra1nfade

0

Joined

Jan 27, 2011

Messages

701

Points

0

I think it's about .7V

plus using grooves and rckstr drivers are cheaper

 

Last edited: Jun 7, 2011