Good morning everyone I will be assembling my laser today since everything comes in the mail, but I wanted to know if my homemade dummy load would function properly:
I'm using a BlitzBuckv4 driver, and a 2W 445nm M140 LD (Vf = 4.0~4.5). This being the case, I would like to set my driver to 1.8 amps (what I have seen as a relatively safe operating current for this specific diode). I already get the gist of how to go about measuring, I just want to know if I used the correct diodes and correct amount:thinking:
This is the dummy: Driver Board (+) -> 1ohm 10W resistor -> 1N5404 -> 1N5404 -> 1N5404 -> 1N5404 -> Driver Board (-)
I figure using 1N5404 x4 since they drop about .85V (correct me if I'm wrong) at around 1.8 A. .85 * 4 = 3.4V. Then add the Vf of the resistor which, also after some research, seems to be 1V, so I have a total of 4.4V drop, which is within the range of the 445nm's calculated Vf. I know to measure with a DMM around the resistor.
So...will this lil rig work? Or do I need to add one more 1N5404? Also, I can't seem to find out if it matters whether I test this out with one battery or two, and what I can do for a temporary replacement of two x 18650 (S4 host with battery extension) without damaging anything or reducing power output? I've found nothing through research, and I just want to confirm the "yes" or "no." One more thing, I live in South Florida.. can I buy these batteries locally somewhere? Or is that highly inconceivable due to their nature and relatively low demand? I appreciate the patience, considering I want to make this lil' beast perfectly :drool:
I'm using a BlitzBuckv4 driver, and a 2W 445nm M140 LD (Vf = 4.0~4.5). This being the case, I would like to set my driver to 1.8 amps (what I have seen as a relatively safe operating current for this specific diode). I already get the gist of how to go about measuring, I just want to know if I used the correct diodes and correct amount:thinking:
This is the dummy: Driver Board (+) -> 1ohm 10W resistor -> 1N5404 -> 1N5404 -> 1N5404 -> 1N5404 -> Driver Board (-)
I figure using 1N5404 x4 since they drop about .85V (correct me if I'm wrong) at around 1.8 A. .85 * 4 = 3.4V. Then add the Vf of the resistor which, also after some research, seems to be 1V, so I have a total of 4.4V drop, which is within the range of the 445nm's calculated Vf. I know to measure with a DMM around the resistor.
So...will this lil rig work? Or do I need to add one more 1N5404? Also, I can't seem to find out if it matters whether I test this out with one battery or two, and what I can do for a temporary replacement of two x 18650 (S4 host with battery extension) without damaging anything or reducing power output? I've found nothing through research, and I just want to confirm the "yes" or "no." One more thing, I live in South Florida.. can I buy these batteries locally somewhere? Or is that highly inconceivable due to their nature and relatively low demand? I appreciate the patience, considering I want to make this lil' beast perfectly :drool: