bobo99
0
- Joined
- May 18, 2011
- Messages
- 128
- Points
- 18
Hey guys, (maybe girls?, probably not 
)
I'll be building my first DIY laser next week with a BDR-S06J, and a V5 Lava Driver. Also picked up a G-1 Lens.
The question is about the driver. I am going to set it to 500mA, and simply use that. With the G-1 that should give me roughly 600-700mw at the dot, based on historical data.
Battery will be either a 18650 or 10440.
This is my limited understanding of a constant current driver, however I don't think I "get it" entirely, and I would simply like you guys to say "yes", or "no you idiot" and then explain why
So the voltage from from that battery will be 4ish V, and then it goes into the driver. The driver "bucks" or "boosts" the voltage, and provides 500ma to the diode. The voltage going to the diode however will be dynamically changing, because that what constant current drivers do, and that is their function. This is the part I'm a little thick on.
Questions:
1) What is the acceptable "voltage range" of the diode?
2) How does the driver know to provide that voltage, and not go "out of bounds" of that voltage range.
3) Why does the voltage dynamically change on the output side going to the diode? Is it because as the battery drains, the voltage drops, so on the output side it is dropping too?
Or am I out to lunch?
Thanks!
Edited Rambling: Or am I making it too complicated?
Is this simply like a wall wart type plug. Rated at 12V and 1A. The load on the wall plug, HAS to use 12V, however it can use "up to 1A", including 0.001A, and everything in between.
This type of (CC circuit) is simply the opposite, where the current is limited, and the load can use "up to" a certain voltage. And I guess the circuit is set up to not go above a certain cutoff voltage, which the majority of laser diodes can handle?
)I'll be building my first DIY laser next week with a BDR-S06J, and a V5 Lava Driver. Also picked up a G-1 Lens.
The question is about the driver. I am going to set it to 500mA, and simply use that. With the G-1 that should give me roughly 600-700mw at the dot, based on historical data.
Battery will be either a 18650 or 10440.
This is my limited understanding of a constant current driver, however I don't think I "get it" entirely, and I would simply like you guys to say "yes", or "no you idiot" and then explain why
So the voltage from from that battery will be 4ish V, and then it goes into the driver. The driver "bucks" or "boosts" the voltage, and provides 500ma to the diode. The voltage going to the diode however will be dynamically changing, because that what constant current drivers do, and that is their function. This is the part I'm a little thick on.
Questions:
1) What is the acceptable "voltage range" of the diode?
2) How does the driver know to provide that voltage, and not go "out of bounds" of that voltage range.
3) Why does the voltage dynamically change on the output side going to the diode? Is it because as the battery drains, the voltage drops, so on the output side it is dropping too?
Or am I out to lunch?
Thanks!
Edited Rambling: Or am I making it too complicated?
Is this simply like a wall wart type plug. Rated at 12V and 1A. The load on the wall plug, HAS to use 12V, however it can use "up to 1A", including 0.001A, and everything in between.
This type of (CC circuit) is simply the opposite, where the current is limited, and the load can use "up to" a certain voltage. And I guess the circuit is set up to not go above a certain cutoff voltage, which the majority of laser diodes can handle?
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